US H financial see small bank that is examining its customers use its website the numbers of online transactions to make per day in the past eight days are as follows 19,62, 52,53, 52,85, 67,72. What is the median of this data said if your answer is not an integer round your answer to one decimal place what is the mean of this data said if your answer is not an integer round your answer to one decimal place

Let's calculate the median and the mean of the given data set.

### Data Set:
19, 62, 52, 53, 52, 85, 67, 72

#### 1. **Calculating the Median:**

The median is the middle value when the data is arranged in ascending order. If there is an even number of observations, the median is the average of the two middle numbers.

1. **Arrange the data in ascending order:**
   \[
   19, 52, 52, 53, 62, 67, 72, 85
   \]

2. **Determine the position of the median:**
   Since there are 8 numbers (an even number of observations), the median will be the average of the 4th and 5th values.

   The 4th value = 53
   The 5th value = 62

   \[
   \text{Median} = \frac{53 + 62}{2} = \frac{115}{2} = 57.5
   \]

#### 2. **Calculating the Mean:**

The mean is the average of the data set.

1. **Sum of the dataLet's calculate the median and the mean of the given data set.

### Data Set:
19, 62, 52, 53, 52, 85, 67, 72

#### 1. **Calculating the Median:**

The median is the middle value when the data is arranged in ascending order. If there is an even number of observations, the median is the average of the two middle numbers.

1. **Arrange the data in ascending order:**
   \[
   19, 52, 52, 53, 62, 67, 72, 85
   \]

2. **Determine the position of the median:**
   Since there are 8 numbers (an even number of observations), the median will be the average of the 4th and 5th values.

   The 4th value = 53
   The 5th value = 62

   \[
   \text{Median} = \frac{53 + 62}{2} = \frac{115}{2} = 57.5
   \]

#### 2. **Calculating the Mean:**

The mean is the average of the data set.

1. **Sum of the **
   \[
   19 + 62 + 52 + 53 + 52 + 85 + 67 + 72 = 462
   \]

2. **Number of observations:**
   \[
   n = 8
   \]

3. **Mean:**
   \[
   \text{Mean} = \frac{462}{8} = 57.75 \approx 57.8 \text{ (rounded to one decimal place)}
   \]

### Final Answers:
- **Median:** 57.5
- **Mean:** 57.8

### Do you want details or have any questions?

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Here are 8 related questions to expand your understanding:

1. What is the mode of the given data set, and how is it calculated?
2. How would the median change if one more data point were added?
3. What is the range of this data set?
4. How would you calculate the variance and standard deviation of this data?
5. Why is the median less affected by extreme values compared to the mean?
6. How do outliers impact the mean and median of a data set?
7. What is the difference between mean, median, and mode in terms of their applications?
8. How would the calculations change if the data set had an odd number of observations?

**Tip:** The median is often preferred over the mean when dealing with skewed data or outliers, as it provides a better central tendency measure in such cases.

Learn how to calculate the median and mean of a data set representing daily online transactions from a small bank's website. Understand the steps involved, including arranging data in ascending order, calculating the median for even numbers of observations, and finding the mean. Suitable for Grades 7-9.

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