Math Problem Statement
Find mean, mode, median
Solution
import pandas as pd
Data extracted from the table
data = { "Height Range (cm)": ["140-150", "150-160", "160-170", "170-180", "180-190"], "Frequency": [3, 5, 12, 15, 5] }
Converting the data into a DataFrame for better manipulation
df = pd.DataFrame(data)
Calculating the mid-points of the height ranges
df["Midpoint"] = df["Height Range (cm)"].apply(lambda x: (int(x.split("-")[0]) + int(x.split("-")[1])) / 2)
Adding a column for the product of frequency and midpoint (fx)
df["fx"] = df["Frequency"] * df["Midpoint"]
Calculating the mean
total_frequency = df["Frequency"].sum() mean = df["fx"].sum() / total_frequency
Calculating the cumulative frequency for median
df["Cumulative Frequency"] = df["Frequency"].cumsum()
Median calculation
n = total_frequency / 2 # Median class is where cumulative frequency >= n median_class_index = df[df["Cumulative Frequency"] >= n].index[0] median_class = df.iloc[median_class_index] median_l = int(median_class["Height Range (cm)"].split("-")[0]) # Lower boundary of median class median_h = 10 # Width of the class interval median_f = median_class["Frequency"] # Frequency of the median class cumulative_f_prev = 0 if median_class_index == 0 else df.iloc[median_class_index - 1]["Cumulative Frequency"]
median = median_l + ((n - cumulative_f_prev) / median_f) * median_h
Mode calculation
The modal class is the one with the highest frequency
mode_class_index = df["Frequency"].idxmax() mode_class = df.iloc[mode_class_index] mode_l = int(mode_class["Height Range (cm)"].split("-")[0]) # Lower boundary of modal class mode_f1 = mode_class["Frequency"] # Frequency of modal class mode_f0 = 0 if mode_class_index == 0 else df.iloc[mode_class_index - 1]["Frequency"] # Frequency of class before modal class mode_f2 = 0 if mode_class_index == len(df) - 1 else df.iloc[mode_class_index + 1]["Frequency"] # Frequency of class after modal class
mode = mode_l + ((mode_f1 - mode_f0) / ((mode_f1 - mode_f0) + (mode_f1 - mode_f2))) * median_h
mean, median, mode(168.5, 170.0, 172.30769230769232)(168.5, 170.0, 172.30769230769232)successThe measures of central tendency for the given data are:
- Mean: 168.5 cm
- Median: 170.0 cm
- Mode: 172.31 cm (approximately)
Would you like a detailed explanation of these calculations or assistance with something else?
Here are 5 follow-up questions to explore further:
- How are the mean, median, and mode applied in real-life scenarios?
- What would happen if the class intervals were uneven?
- How does the calculation change if new data points are added to this set?
- Why is the mode less accurate than the mean or median in some cases?
- Can we visually represent this data to better understand these measures?
Tip: When working with grouped data, always calculate class midpoints for frequency distributions to simplify computations for the mean.
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Math Problem Analysis
Mathematical Concepts
Statistics
Measures of Central Tendency
Grouped Data
Formulas
Mean = Σ(fx) / Σ(f)
Median = L + [(N/2 - CF) / f] * h
Mode = L + [(f1 - f0) / (2f1 - f0 - f2)] * h
Theorems
Concept of grouped frequency distribution
Suitable Grade Level
Grades 9-12
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