Math Problem Statement

Calculate a specific statistical value (likely the mean) from the frequency distribution table provided.

Solution

This image provides a frequency distribution table showing "Nilai" (values) and "Frekuensi" (frequencies). To solve the question, we likely need to find the mean, median, or another statistical value, and the multiple-choice options at the bottom suggest that we need to calculate something specific from this distribution.

Let's break it down step-by-step, assuming we are tasked with calculating the mean (as the provided answer options suggest):

1. Midpoint of each class interval:

The midpoint (xix_i) is calculated as the average of the lower and upper limits of each interval:

  • Midpoint of 1120=11+202=15.5\text{Midpoint of } 11 - 20 = \frac{11 + 20}{2} = 15.5
  • Midpoint of 2130=21+302=25.5\text{Midpoint of } 21 - 30 = \frac{21 + 30}{2} = 25.5
  • Midpoint of 3140=31+402=35.5\text{Midpoint of } 31 - 40 = \frac{31 + 40}{2} = 35.5
  • Midpoint of 4150=41+502=45.5\text{Midpoint of } 41 - 50 = \frac{41 + 50}{2} = 45.5
  • Midpoint of 5160=51+602=55.5\text{Midpoint of } 51 - 60 = \frac{51 + 60}{2} = 55.5
  • Midpoint of 6170=61+702=65.5\text{Midpoint of } 61 - 70 = \frac{61 + 70}{2} = 65.5
  • Midpoint of 7180=71+802=75.5\text{Midpoint of } 71 - 80 = \frac{71 + 80}{2} = 75.5
  • Midpoint of 8190=81+902=85.5\text{Midpoint of } 81 - 90 = \frac{81 + 90}{2} = 85.5
  • Midpoint of 91100=91+1002=95.5\text{Midpoint of } 91 - 100 = \frac{91 + 100}{2} = 95.5

2. Mean Formula:

The formula for the mean (xˉ\bar{x}) in a frequency distribution is: xˉ=(fixi)fi\bar{x} = \frac{\sum (f_i \cdot x_i)}{\sum f_i} Where:

  • fif_i is the frequency of each class,
  • xix_i is the midpoint of each class.

Now, we multiply each midpoint by the corresponding frequency and sum them up.

3. Calculations:

Class IntervalMidpoint xix_iFrequency fif_ifixif_i \cdot x_i
11 – 2015.5346.5
21 – 3025.57178.5
31 – 4035.510355
41 – 5045.516728
51 – 6055.5201110
61 – 7065.514917
71 – 8075.510755
81 – 9085.56513
91 – 10095.54382

Now, summing up the products fixif_i \cdot x_i:

(fixi)=46.5+178.5+355+728+1110+917+755+513+382=4985\sum (f_i \cdot x_i) = 46.5 + 178.5 + 355 + 728 + 1110 + 917 + 755 + 513 + 382 = 4985

4. Total Frequency fi=90\sum f_i = 90.

5. Mean:

xˉ=49859055.39\bar{x} = \frac{4985}{90} \approx 55.39

The closest option to this result is 56 (option d).


Would you like a more detailed explanation or to ask about other calculations?

Here are 5 related questions you may want to explore:

  1. How do you calculate the median from a frequency distribution?
  2. How would you determine the mode in this dataset?
  3. What if the class intervals were unequal—how would the calculation change?
  4. How can we represent this data graphically (histogram, frequency polygon)?
  5. What is the significance of the standard deviation for this dataset?

Tip: Always check if the class intervals are equal, as unequal intervals require additional adjustments when calculating the mean, median, or mode.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Statistics
Frequency Distribution
Mean

Formulas

Mean formula: x̄ = Σ(f_i * x_i) / Σf_i

Theorems

-

Suitable Grade Level

Grades 8-10