https://file.aiquickdraw.com/mathbot/file/17273168445655txnfjlo.jpg

The table in your image seems to represent a frequency distribution, likely based on age intervals or scores. The request, "Cari rata-rata (x̄)" translates from Indonesian as "Find the average (mean) (x̄)".

To calculate the mean, we need the following information:

1. **Class intervals (or scores):** Represented by the intervals such as 45-49, 50-54, etc.
2. **Frequencies (f):** These are the values below "skor," which are the counts of occurrences for each interval.

### Steps to calculate the mean:

1. **Midpoints (m):** First, calculate the midpoint for each class interval by averaging the lower and upper boundaries. For example, for 45-49, the midpoint would be:
   \[
   m = \frac{45 + 49}{2} = 47
   \]
2. **Multiply midpoints by frequencies:** For each class interval, multiply the midpoint by the corresponding frequency (f).

3. **Sum of all midpoint-frequency products:** Add up all the products from step 2.

4. **Sum of all frequencies:** Add all the frequencies.

5. **Mean (x̄):** The formula for the mean is:
   \[
   \bar{x} = \frac{\Sigma (f \cdot m)}{\Sigma f}
   \]

Would you like me to calculate this for you using the values from the table?

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**5 Related Questions:**

1. How is a class midpoint calculated in a frequency distribution?
2. What is the difference between a weighted average and a simple average?
3. How do you find the median from a frequency table?
4. What is the role of frequencies in calculating statistical measures like the mean?
5. How do you determine the mode from a grouped frequency distribution?

**Tip:** When working with frequency distributions, using midpoints is key to simplifying calculations like the mean and variance.

Cari rata-rata (Find the average) based on a frequency distribution table

Learn how to calculate the mean (average) from a frequency distribution table. This problem involves determining midpoints, multiplying them by frequencies, and finding the mean using the formula Σ(f * m) / Σf. Suitable for students in Grades 9-12.

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