A tanker truck carrying 2.01×103 kgkg of concentrated sulfuric acid solution tips over and spills its load. The sulfuric acid solution is 95.0%% H2SO4H2SO4 by mass and has a density of 1.84 g/Lg/L.

To analyze the spill and calculate various properties, let’s break down the problem based on the given dataTo analyze the spill and calculate various properties, let’s break down the problem based on the given 

### Given:
- **Mass of the sulfuric acid solution:** \( 2.01 \times 10^3 \, \text{kg} \) (or 2010 kg)
- **Mass percentage of \( \text{H}_2\text{SO}_4 \) in the solution:** 95.0%
- **Density of the sulfuric acid solution:** \( 1.84 \, \text{g/mL} \) (or \( 1.84 \, \text{kg/L} \))

We can use this information to calculate several properties:

### Step 1: Calculate the mass of pure sulfuric acid in the solution

Since the solution is 95.0% sulfuric acid by mass, the mass of pure sulfuric acid \( \text{H}_2\text{SO}_4 \) is:

\[
\text{Mass of } \text{H}_2\text{SO}_4 = 95.0\% \times 2010 \, \text{kg}
\]

\[
\text{Mass of } \text{H}_2\text{SO}_4 = 0.95 \times 2010 = 1909.5 \, \text{kg}
\]

So, the spill contains **1909.5 kg** of pure sulfuric acid.

### Step 2: Calculate the volume of the sulfuric acid solution

We can calculate the volume of the sulfuric acid solution using its total mass and density. The density \( \rho \) is given as \( 1.84 \, \text{kg/L} \), and the total mass of the solution is 2010 kg. The formula for volume is:

\[
\text{Volume} = \frac{\text{Mass}}{\text{Density}}
\]

Substituting the known values:

\[
\text{Volume} = \frac{2010 \, \text{kg}}{1.84 \, \text{kg/L}} = 1092.39 \, \text{L}
\]

So, the volume of the sulfuric acid solution is approximately **1092.39 liters**.

### Step 3: Calculate the volume of pure sulfuric acid in the solution

Now, let’s calculate the volume of just the sulfuric acid, \( \text{H}_2\text{SO}_4 \), using its mass (from Step 1) and the same density, assuming the solution’s density is a good approximation for the pure acid.

\[
\text{Volume of } \text{H}_2\text{SO}_4 = \frac{1909.5 \, \text{kg}}{1.84 \, \text{kg/L}} = 1037.77 \, \text{L}
\]

So, the pure sulfuric acid occupies approximately **1037.77 liters**.

### Final Summary:

- **Mass of pure \( \text{H}_2\text{SO}_4 \):** 1909.5 kg
- **Total volume of the sulfuric acid solution:** 1092.39 liters
- **Volume of pure \( \text{H}_2\text{SO}_4 \):** 1037.77 liters

---

Would you like further details or to explore related questions?

Here are five related questions:
1. How would the volume change if the solution were 90% sulfuric acid instead of 95%?
2. What would happen to the density of the solution if more water were added?
3. How would you neutralize this spill with sodium hydroxide, and how much would be needed?
4. What is the molarity of sulfuric acid in this solution?
5. How would the density of the solution change if the temperature increased?

**Tip:** In problems involving mass percentage, always calculate the mass of the substance of interest first before converting between mass and volume using the density!

A tanker truck carrying 2.01×10^3 kg of concentrated sulfuric acid solution tips over and spills its load. The sulfuric acid solution is 95.0% H2SO4 by mass and has a density of 1.84 g/L.

Analyze a spill of 2010 kg of 95% sulfuric acid solution with a density of 1.84 g/L. This problem involves key concepts like percentage calculations and density-mass-volume relationships, ideal for Grades 10-12.

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