Math Problem Statement

Find the magnitude of vector u given the initial point (1, 7) and the terminal point (7, 4).

Solution

To find the magnitude of the vector u\vec{u}, we need to first determine the coordinates of its initial and terminal points from the graph.

From the image:

  • The initial point of vector u\vec{u} is at (1,7)(1, 7).
  • The terminal point of vector u\vec{u} is at (7,4)(7, 4).

The formula for the magnitude (or length) of a vector u=x2x1,y2y1\vec{u} = \langle x_2 - x_1, y_2 - y_1 \rangle is:

u=(x2x1)2+(y2y1)2|\vec{u}| = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Substituting the points (x1,y1)=(1,7)(x_1, y_1) = (1, 7) and (x2,y2)=(7,4)(x_2, y_2) = (7, 4):

u=(71)2+(47)2|\vec{u}| = \sqrt{(7 - 1)^2 + (4 - 7)^2}

Now I will calculate the result.The magnitude of vector u\vec{u} is approximately 6.716.71, rounded to the nearest hundredth.

Would you like further details or have any questions about this calculation?

Here are 5 related questions for practice:

  1. How do you calculate the direction of a vector given its points?
  2. What is the difference between the magnitude and direction of a vector?
  3. How do you find the unit vector in the direction of a given vector?
  4. Can you calculate the distance between two points using the same formula as vector magnitude?
  5. What are the components of a vector if its magnitude is known?

Tip: Always remember to square the differences in both the x and y coordinates before adding them when calculating the magnitude of a vector.

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Math Problem Analysis

Mathematical Concepts

Vectors
Coordinate Geometry
Distance Formula

Formulas

Magnitude of vector formula: |u| = √[(x2 - x1)^2 + (y2 - y1)^2]

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 9-12