The force between two identical charges is seprated by 0.01m is equal to 95N. What is the magnitude of the two charges?

To find the magnitude of the two charges, we can use Coulomb's Law, which states:

\[ F = \frac{k \cdot |q_1 \cdot q_2|}{r^2} \]

Given:
- The force \( F = 95 \, \text{N} \)
- The separation \( r = 0.01 \, \text{m} \)
- \( k = 8.99 \times 10^9 \, \text{N m}^2/\text{C}^2 \)

Since the charges are identical, let \( q_1 = q_2 = q \). Thus, the equation becomes:

\[ F = \frac{k \cdot q^2}{r^2} \]

We can solve for \( q \):

\[ 95 = \frac{8.99 \times 10^9 \cdot q^2}{(0.01)^2} \]

First, solve for \( q^2 \):

\[ 95 = \frac{8.99 \times 10^9 \cdot q^2}{0.0001} \]

\[ 95 = 8.99 \times 10^{13} \cdot q^2 \]

\[ q^2 = \frac{95}{8.99 \times 10^{13}} \]

\[ q^2 \approx 1.057 \times 10^{-12} \]

Finally, solve for \( q \):

\[ q \approx \sqrt{1.057 \times 10^{-12}} \]

\[ q \approx 1.028 \times 10^{-6} \, \text{C} \]

So, the magnitude of each charge is approximately \( 1.028 \, \mu\text{C} \).

Would you like more details or have any questions?

### Relative Questions:
1. What is Coulomb's Law?
2. How does the distance between charges affect the force between them?
3. What is the value of Coulomb's constant \( k \)?
4. How would the force change if the charges were doubled?
5. How does the medium between charges affect the force?
6. What are the units of charge in the SI system?
7. How can Coulomb's Law be applied to point charges?
8. What happens to the force if the distance is halved?

### Tip:
Always ensure units are consistent when using physical equations to avoid errors in calculations.

Learn how to calculate the magnitude of two identical charges separated by 0.01m, given a force of 95N using Coulomb's Law. Understand the principles of electrostatics and the application of Coulomb's Law formula. Suitable for high school students.

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