https://file.aiquickdraw.com/mathbot/file/1728916428200dmp0nhaq.jpg

The problem in the image seems to involve a rotating object. Here's a translated and interpreted version of the problem:

"A rotating object with a length of rope of 5 meters and an angular velocity of 2.14 rad/s. The linear velocity of the rotating object is?"

To solve this, we can use the formula that relates linear velocity \( v \) to angular velocity \( \omega \) and the radius (or length of the rope) \( r \):

\[
v = \omega \times r
\]

Where:
- \( \omega = 2.14 \, \text{rad/s} \) (angular velocity),
- \( r = 5 \, \text{m} \) (length of the rope).

Let's calculate the linear velocity:

\[
v = 2.14 \, \text{rad/s} \times 5 \, \text{m} = 10.7 \, \text{m/s}
\]

It seems like the answer closest to this is **C. 12 m/s** (likely rounded).

Would you like more details or have any questions?

### Related questions:
1. What is the difference between angular velocity and linear velocity?
2. How would the velocity change if the length of the rope increased?
3. What happens to the linear velocity if the angular velocity is doubled?
4. Can you calculate the centripetal acceleration of the object?
5. How does this problem relate to circular motion in physics?

### Tip:
For circular motion, always keep in mind that the linear speed depends directly on the angular velocity and the radius!

A rotating object with a length of rope of 5 meters and an angular velocity of 2.14 rad/s. The linear velocity of the rotating object is?

Solve a physics problem involving a rotating object with a 5-meter rope and angular velocity of 2.14 rad/s. Learn how to use the formula v = ω × r to find the linear velocity. Suitable for high school students in Grades 9-12.

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