Math Problem Statement
Calculate the limits of each of the following sequences. If a sequence converges, enter its limit. If a sequence diverges, enter the letter X.
a. {sin(5n)/n} b. {sin(4n)/n} c. {sin(π(6n+1)/2) d. {nsin(6πn)}
Solution
Let's analyze each sequence one by one:
(a)
- The function is bounded, meaning that for any , .
- As , the denominator grows without bound while oscillates between -1 and 1.
- Therefore, as .
Limit: 0
(b)
- Similarly, is bounded by -1 and 1.
- As , the denominator increases without bound while oscillates.
- Hence, as .
Limit: 0
(c)
- First, simplify the expression inside the sine function: Using the periodicity of sine, , we get:
- Therefore, this sequence simplifies to for all .
Limit: 1
(d)
- The term is a multiple of , and we know that for any integer .
- Thus, for all .
Therefore, .
Limit: 0
Summary of Limits:
- (a)
- (b)
- (c)
- (d)
Would you like more details on any specific sequence?
Relative Questions:
- What is the general method to calculate limits for trigonometric sequences?
- Why do sine functions oscillate, and how does this affect limits?
- How does periodicity of trigonometric functions impact the convergence of sequences?
- What are common types of divergent sequences in trigonometry?
- How does L'Hopital's Rule apply to limit problems involving trigonometric functions?
Tip:
Always check for bounded behavior in oscillating functions like sine or cosine to determine the convergence behavior of sequences.
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Math Problem Analysis
Mathematical Concepts
Limits of Sequences
Trigonometric Functions
Oscillating Functions
Formulas
lim (n→∞) sin(kn)/n = 0 (for bounded sin(kn))
lim (n→∞) nsin(kπn) = 0 (for kπn multiples of 2π)
Sine periodicity: sin(x + 2πk) = sin(x)
Theorems
Boundedness of Sine and Cosine
Squeeze Theorem (for oscillating functions)
Periodicity of Trigonometric Functions
Suitable Grade Level
Grades 11-12
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