Math Problem Statement

Calculate the following limit of the function f as x approaches infinity. What can you conclude about the convergence of the sequence a_n?

Solution

Let's go through each question in detail.

Question 1

We are given the function: f(x)=exx+5f(x) = \frac{e^{-x}}{x} + 5 and the sequence: an=enn+5a_n = \frac{e^{-n}}{n} + 5

We need to determine the behavior of f(x)f(x) as xx \to \infty and make conclusions about the convergence of the sequence ana_n.

  1. Limit of f(x)f(x) as xx \to \infty:

    • As xx \to \infty, the term exe^{-x} (which is 1ex\frac{1}{e^x}) approaches 0 very quickly. Therefore, exx0\frac{e^{-x}}{x} \to 0 as xx \to \infty.
    • This makes f(x)5f(x) \to 5 as xx \to \infty.
  2. Behavior of the sequence ana_n:

    • Since an=enn+5a_n = \frac{e^{-n}}{n} + 5, as nn \to \infty, enn\frac{e^{-n}}{n} will also approach 0 (due to the exponential decay of ene^{-n}).
    • Thus, an5a_n \to 5 as nn \to \infty, indicating that the sequence converges to 5.

Therefore, the correct answer is:

  • The limit of f(x)f(x) as xx \to \infty is L=5L = 5, and the sequence ana_n will converge to the same limit.

Question 2

The sequence is defined recursively as: an+1=34an1,a0=1a_{n+1} = \frac{3}{4}a_n - 1, \quad a_0 = -1

Let's examine the behavior of this sequence.

  1. Recursive Analysis:

    • We can calculate a few terms to see the pattern:
      • a0=1a_0 = -1
      • a1=34(1)1=341=74a_1 = \frac{3}{4}(-1) - 1 = -\frac{3}{4} - 1 = -\frac{7}{4}
      • a2=34(74)1=21161=3716a_2 = \frac{3}{4} \left(-\frac{7}{4}\right) - 1 = -\frac{21}{16} - 1 = -\frac{37}{16}
    • The sequence appears to be decreasing.
  2. Long-term behavior:

    • Since 34<1\left| \frac{3}{4} \right| < 1, this sequence will tend towards a stable value as nn \to \infty.
    • A sequence defined by an+1=ran+ca_{n+1} = r a_n + c (where r<1|r| < 1) tends to the fixed point L=c1rL = \frac{c}{1 - r}.
    • Here, r=34r = \frac{3}{4} and c=1c = -1, so the fixed point is: L=1134=114=4L = \frac{-1}{1 - \frac{3}{4}} = \frac{-1}{\frac{1}{4}} = -4

Thus, the sequence converges to 4-4 and is decreasing and bounded below.

The correct answer is:

  • Decreasing and bounded below.

Would you like additional details or have any questions?

Related Questions

  1. How would the solution change if f(x)=ex2x+5f(x) = \frac{e^{-x^2}}{x} + 5 instead?
  2. What if an=en2n+5a_n = \frac{e^{-n^2}}{n} + 5; would it converge to the same limit?
  3. How can you determine if a sequence is bounded or unbounded?
  4. For recursive sequences, how does the initial term a0a_0 affect long-term behavior?
  5. Can recursive sequences have multiple fixed points?

Tip

In recursive sequences, a constant ratio with r<1|r| < 1 typically leads to convergence towards a steady-state (fixed point).

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Math Problem Analysis

Mathematical Concepts

Calculus
Limits
Sequences and Series
Convergence

Formulas

Limit of a function as x approaches infinity
Limit of a sequence as n approaches infinity

Theorems

Limit definition for functions
Convergence criteria for sequences

Suitable Grade Level

Grades 10-12