Math Problem Statement

Consider the following data from a sample of n=7.

x 178 176 174 166 172 172 174 y 58 55 54 47 52 53 55

The y-intercept of the least squares line is -99.2105263157895. Compute the slope of the least squares line and enter the equation of the least squares line below. (As always, if you round, make sure you do so correctly, only round your final answer, and keep at least three decimal places.)

The least squares line is y =

Regardless of what answer you actually got, suppose your regression equation were y= -80 + 0.8x.

For x = 177, the hypothetical line predicts the value of y will be

Solution

Let's first compute the slope of the least squares line. The slope (b1b_1) of the least squares line can be computed using the following formula:

b1=nxyxynx2(x)2b_1 = \frac{n\sum{xy} - \sum{x}\sum{y}}{n\sum{x^2} - (\sum{x})^2}

Where:

  • nn is the number of data points (7 in this case),
  • xy\sum{xy} is the sum of the product of each xx and corresponding yy,
  • x\sum{x} is the sum of all xx values,
  • y\sum{y} is the sum of all yy values,
  • x2\sum{x^2} is the sum of the squares of all xx values.

Step 1: Compute the necessary sums

  • x=[178,176,174,166,172,172,174]x = [178, 176, 174, 166, 172, 172, 174]
  • y=[58,55,54,47,52,53,55]y = [58, 55, 54, 47, 52, 53, 55]

Now let's calculate:

  1. x=178+176+174+166+172+172+174\sum{x} = 178 + 176 + 174 + 166 + 172 + 172 + 174
  2. y=58+55+54+47+52+53+55\sum{y} = 58 + 55 + 54 + 47 + 52 + 53 + 55
  3. xy=(178×58)+(176×55)+(174×54)+(166×47)+(172×52)+(172×53)+(174×55)\sum{xy} = (178 \times 58) + (176 \times 55) + (174 \times 54) + (166 \times 47) + (172 \times 52) + (172 \times 53) + (174 \times 55)
  4. x2=(1782)+(1762)+(1742)+(1662)+(1722)+(1722)+(1742)\sum{x^2} = (178^2) + (176^2) + (174^2) + (166^2) + (172^2) + (172^2) + (174^2)

I'll calculate these values next.The computed sums are:

  • x=1212\sum{x} = 1212
  • y=374\sum{y} = 374
  • xy=64832\sum{xy} = 64832
  • x2=209936\sum{x^2} = 209936

Step 2: Compute the slope (b1b_1) using the formula:

b1=nxyxynx2(x)2b_1 = \frac{n\sum{xy} - \sum{x}\sum{y}}{n\sum{x^2} - (\sum{x})^2}

Let me calculate this value for you.The slope of the least squares line is b1=0.882b_1 = 0.882 (rounded to three decimal places).

Step 3: Find the equation of the least squares line

The equation of the least squares line is given by:

y=b0+b1xy = b_0 + b_1x

Where:

  • b1b_1 is the slope we just calculated,
  • b0b_0 (the y-intercept) is provided as 99.2105263157895-99.2105263157895.

Thus, the equation of the least squares line is:

y=99.211+0.882xy = -99.211 + 0.882x

Step 4: Hypothetical regression equation

If the regression equation were y=80+0.8xy = -80 + 0.8x, for x=177x = 177, the predicted value of yy would be:

y=80+0.8(177)y = -80 + 0.8(177)

Let me calculate this value for you.For x=177x = 177, the hypothetical regression line y=80+0.8xy = -80 + 0.8x predicts that y=61.6y = 61.6.

Would you like further details on any part of this solution?

Here are some related questions to explore:

  1. How do you calculate the y-intercept if it's not given?
  2. What are residuals in a regression model?
  3. How do you interpret the slope in a real-world context?
  4. How do you calculate the coefficient of determination R2R^2?
  5. How can you perform a significance test for the slope?

Tip: Always check the assumptions of linear regression before relying on predictions from your model.

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Math Problem Analysis

Mathematical Concepts

Statistics
Linear Regression
Least Squares Method

Formulas

Slope of the least squares line: b1 = (n∑xy - ∑x∑y) / (n∑x² - (∑x)²)
Equation of a straight line: y = b0 + b1x

Theorems

Least Squares Regression

Suitable Grade Level

Undergraduate/High School