Math Problem Statement
Solution
Let's break down the problem from the image you've uploaded.
We are told that:
- Six Grade 2 learners sit around one table.
- When two tables are joined, eight learners sit around them.
We need to calculate how many learners would sit at different numbers of tables: five tables, twenty-five tables, and two hundred tables.
Step-by-step breakdown:
- For one table: 6 learners sit around one table.
- For two tables: 8 learners sit around the two joined tables.
From this, we can deduce that by joining an additional table to an existing setup, 2 more learners are added.
This suggests a pattern where after the first table, each additional table adds 2 more learners.
Formula Derivation:
- For tables: The number of learners is 6 learners (for the first table) plus 2 learners for each additional table.
- General formula:
Now we apply this formula to the given scenarios:
2.4.1 Five tables:
So, 14 learners would sit at five tables.
2.4.2 Twenty-five tables:
So, 54 learners would sit at twenty-five tables.
2.4.3 Two hundred tables:
So, 404 learners would sit at two hundred tables.
Summary:
- For 5 tables: 14 learners.
- For 25 tables: 54 learners.
- For 200 tables: 404 learners.
Would you like further clarification or additional details?
Relative Questions:
- What would be the number of learners for 10 tables?
- How many learners would sit at 50 tables?
- What if we used 3 tables instead of 2 for the same calculation pattern?
- How many learners would sit if each new table added 3 learners instead of 2?
- Can this pattern apply if the tables form a different geometric arrangement?
Tip: Always check if there is a pattern in the changes (increase or decrease) between cases when calculating a series of related values. This helps in formulating general rules.
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Math Problem Analysis
Mathematical Concepts
Arithmetic Sequences
Basic Algebra
Formulas
Learners = 6 + 2 × (number of tables - 1)
Theorems
-
Suitable Grade Level
Grade 2-3
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