Math Problem Statement
.4 Six Grade 2 learners sit around one table; the teacher joins the two tables, and eight sit on the two tables. Calculate how many learners would sit at the following tables: 2.4.1 Five tables (5) 2.4.2 Twenty-five tables (5) 2.4.3 Two hundred tables (5) N.B Show the formula and
Solution
To solve the problem of how many learners sit at multiple tables, let's first find the pattern or formula that describes the relationship between the number of tables and the number of learners.
Step-by-Step Solution:
- Initially, 6 learners sit around 1 table.
- When the teacher joins 2 tables together, 8 learners can sit around 2 tables.
From this, we see that:
- 1 table accommodates 6 learners.
- 2 tables accommodate 8 learners.
The difference between the learners added per table beyond the first is 2 learners.
General Formula:
From this pattern, we can derive that the first table accommodates 6 learners, and each additional table adds 2 more learners. This leads us to the formula:
Now let's calculate for the given number of tables.
2.4.1 Five tables
So, 14 learners can sit at 5 tables.
2.4.2 Twenty-five tables
So, 54 learners can sit at 25 tables.
2.4.3 Two hundred tables
So, 404 learners can sit at 200 tables.
Formula Summary:
The general formula to calculate the number of learners is:
Let me know if you'd like further details or have any questions.
Here are 5 related questions:
- How many learners would sit at 10 tables?
- If 18 learners are sitting, how many tables are there?
- How would the seating change if each additional table added 3 learners instead of 2?
- How many learners sit around 50 tables?
- What is the seating capacity for 100 tables?
Tip: Always double-check the pattern to ensure consistency when solving similar problems.
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Math Problem Analysis
Mathematical Concepts
Patterns
Algebra
Arithmetic Sequences
Formulas
Number of learners = 6 + 2 × (Number of tables - 1)
Theorems
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Suitable Grade Level
Grades 3-4
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