Math Problem Statement

9.7 10.0 10.0 9.0 10.8 8.7 9.5 9.2 what is the interquartile range

Solution

To find the interquartile range (IQR), follow these steps:

  1. Arrange the data in ascending order: 8.7,9.0,9.2,9.5,9.7,10.0,10.0,10.88.7, 9.0, 9.2, 9.5, 9.7, 10.0, 10.0, 10.8

  2. Find the first quartile (Q1): Q1 is the median of the lower half of the data (excluding the overall median if the data set is odd).

    Lower half: 8.7,9.0,9.2,9.58.7, 9.0, 9.2, 9.5

    The median of this set (average of 9.0 and 9.2): Q1=9.0+9.22=9.1Q1 = \frac{9.0 + 9.2}{2} = 9.1

  3. Find the third quartile (Q3): Q3 is the median of the upper half of the data.

    Upper half: 9.7,10.0,10.0,10.89.7, 10.0, 10.0, 10.8

    The median of this set (average of 10.0 and 10.0): Q3=10.0Q3 = 10.0

  4. Calculate the interquartile range (IQR): IQR=Q3Q1=10.09.1=0.9\text{IQR} = Q3 - Q1 = 10.0 - 9.1 = 0.9

Thus, the interquartile range (IQR) is 0.9.

Would you like further details or have any questions?

Here are 5 related questions to expand on this topic:

  1. What does the interquartile range tell us about data spread?
  2. How does IQR help in detecting outliers in a data set?
  3. Can you explain the difference between IQR and range?
  4. How can the quartiles be visually represented on a box plot?
  5. How would the IQR change if an additional data point were added?

Tip: IQR is a robust measure of variability, less affected by outliers compared to range.

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Math Problem Analysis

Mathematical Concepts

Statistics
Quartiles
Interquartile Range

Formulas

IQR = Q3 - Q1
Median calculation

Theorems

Concept of Quartiles
Interquartile Range

Suitable Grade Level

Grades 8-10