Math Problem Statement

10.0 90.6 48.5 50.4 57.4 99.6 0.0 5.0 0.0 0.0 5.0 2.0 10.5 5.0 47.0 0.0 5.0 54.0 0.0 48.6 fine interquartile range

Solution

To calculate the interquartile range (IQR), we need to follow these steps:

  1. Sort the data in ascending order.
  2. Find the first quartile (Q1), which is the median of the lower half of the data.
  3. Find the third quartile (Q3), which is the median of the upper half of the data.
  4. Calculate the IQR using the formula: IQR=Q3Q1IQR = Q3 - Q1

Step 1: Sort the data

Here is the sorted version of your dataTo calculate the interquartile range (IQR), we need to follow these steps:

  1. Sort the data in ascending order.
  2. Find the first quartile (Q1), which is the median of the lower half of the data.
  3. Find the third quartile (Q3), which is the median of the upper half of the data.
  4. Calculate the IQR using the formula: IQR=Q3Q1IQR = Q3 - Q1

Step 1: Sort the data

Here is the sorted version of your 0.0,0.0,0.0,0.0,2.0,5.0,5.0,5.0,5.0,10.0,10.5,47.0,48.5,48.6,50.4,54.0,57.4,90.6,99.60.0, 0.0, 0.0, 0.0, 2.0, 5.0, 5.0, 5.0, 5.0, 10.0, 10.5, 47.0, 48.5, 48.6, 50.4, 54.0, 57.4, 90.6, 99.6

Step 2: Find the First Quartile (Q1)

  • The lower half of the dataTo calculate the interquartile range (IQR), we need to follow these steps:
  1. Sort the data in ascending order.
  2. Find the first quartile (Q1), which is the median of the lower half of the data.
  3. Find the third quartile (Q3), which is the median of the upper half of the data.
  4. Calculate the IQR using the formula: IQR=Q3Q1IQR = Q3 - Q1

Step 1: Sort the data

Here is the sorted version of your 0.0,0.0,0.0,0.0,2.0,5.0,5.0,5.0,5.0,10.0,10.5,47.0,48.5,48.6,50.4,54.0,57.4,90.6,99.60.0, 0.0, 0.0, 0.0, 2.0, 5.0, 5.0, 5.0, 5.0, 10.0, 10.5, 47.0, 48.5, 48.6, 50.4, 54.0, 57.4, 90.6, 99.6

Step 2: Find the First Quartile (Q1)

  • The lower half of the
    0.0,0.0,0.0,0.0,2.0,5.0,5.0,5.0,5.00.0, 0.0, 0.0, 0.0, 2.0, 5.0, 5.0, 5.0, 5.0
  • Q1 is the median of this set. Since there are 9 data points, Q1 is the 5th value: Q1=2.0Q1 = 2.0

Step 3: Find the Third Quartile (Q3)

  • The upper half of the dataTo calculate the interquartile range (IQR), we need to follow these steps:
  1. Sort the data in ascending order.
  2. Find the first quartile (Q1), which is the median of the lower half of the data.
  3. Find the third quartile (Q3), which is the median of the upper half of the data.
  4. Calculate the IQR using the formula: IQR=Q3Q1IQR = Q3 - Q1

Step 1: Sort the data

Here is the sorted version of your 0.0,0.0,0.0,0.0,2.0,5.0,5.0,5.0,5.0,10.0,10.5,47.0,48.5,48.6,50.4,54.0,57.4,90.6,99.60.0, 0.0, 0.0, 0.0, 2.0, 5.0, 5.0, 5.0, 5.0, 10.0, 10.5, 47.0, 48.5, 48.6, 50.4, 54.0, 57.4, 90.6, 99.6

Step 2: Find the First Quartile (Q1)

  • The lower half of the
    0.0,0.0,0.0,0.0,2.0,5.0,5.0,5.0,5.00.0, 0.0, 0.0, 0.0, 2.0, 5.0, 5.0, 5.0, 5.0
  • Q1 is the median of this set. Since there are 9 data points, Q1 is the 5th value: Q1=2.0Q1 = 2.0

Step 3: Find the Third Quartile (Q3)

  • The upper half of the
    10.0,10.5,47.0,48.5,48.6,50.4,54.0,57.4,90.6,99.610.0, 10.5, 47.0, 48.5, 48.6, 50.4, 54.0, 57.4, 90.6, 99.6
  • Q3 is the median of this set. The middle value is the 5th number: Q3=48.6Q3 = 48.6

Step 4: Calculate the Interquartile Range (IQR)

IQR=Q3Q1=48.62.0=46.6IQR = Q3 - Q1 = 48.6 - 2.0 = 46.6

So, the Interquartile Range (IQR) is 46.6.

Would you like more details or have any questions?


Follow-up Questions:

  1. How is the interquartile range useful in statistical analysis?
  2. What is the difference between IQR and standard deviation?
  3. Can outliers affect the interquartile range calculation?
  4. How can you visually represent IQR in a dataset?
  5. What is the purpose of quartiles in data distribution?

Tip: The interquartile range is often used to identify outliers in data, as values falling 1.5 times above or below the IQR are considered outliers.

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Math Problem Analysis

Mathematical Concepts

Descriptive Statistics
Interquartile Range
Quartiles

Formulas

IQR = Q3 - Q1

Theorems

Interquartile Range

Suitable Grade Level

Grades 8-10