Math Problem Statement

$ 1,201 = $ 370 * ( 1+r/100 ) ^ 19

Solution

To solve for rr in the equation:

1201=370×(1+r100)191201 = 370 \times \left(1 + \frac{r}{100}\right)^{19}

Steps:

  1. Divide both sides by 370 to simplify the equation: 1201370=(1+r100)19\frac{1201}{370} = \left(1 + \frac{r}{100}\right)^{19} 3.2473(1+r100)193.2473 \approx \left(1 + \frac{r}{100}\right)^{19}

  2. Take the 19th root of both sides to remove the exponent: 3.247319=1+r100\sqrt[19]{3.2473} = 1 + \frac{r}{100}

  3. Subtract 1 from both sides to isolate r100\frac{r}{100}: 3.2473191=r100\sqrt[19]{3.2473} - 1 = \frac{r}{100}

  4. Multiply both sides by 100 to solve for rr: r=100×(3.2473191)r = 100 \times \left(\sqrt[19]{3.2473} - 1\right)

Calculation:

Now, compute the value:

3.2473191.0619\sqrt[19]{3.2473} \approx 1.0619 r100×(1.06191)=100×0.0619=6.19%r \approx 100 \times (1.0619 - 1) = 100 \times 0.0619 = 6.19\%

So, the value of rr is approximately 6.19%.

Would you like any further explanation, or do you have any questions?

Relative Questions:

  1. How does the length of the investment period affect the interest rate required to reach a certain amount?
  2. Why is it necessary to take the 19th root in this equation?
  3. How would the interest rate change if the final amount were different, say $1,500?
  4. What are the practical applications of solving for the interest rate in financial planning?
  5. How does this calculation differ when considering simple interest instead of compound interest?

Tip:

When solving for the interest rate in compound interest problems, taking the root corresponding to the time period is essential to accurately determine the rate over that period.

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Math Problem Analysis

Mathematical Concepts

Exponential Functions
Roots and Radicals
Compound Interest

Formulas

Compound Interest Formula

Theorems

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Suitable Grade Level

Grades 10-12