Math Problem Statement

How far does it travel horizontally

How far does it travel horizontally?

Solution

To solve this, we can apply the principles of projectile motion. Given dataTo solve this, we can apply the principles of projectile motion. Given

  • Launch angle, θ=37.0\theta = 37.0^\circ
  • Initial velocity, v0=25.0m/sv_0 = 25.0 \, \text{m/s}

We want to find the horizontal range of the football, or how far it travels horizontally. This requires calculating both the horizontal and vertical components of the initial velocity, determining the time of flight, and then finding the range.

Step-by-Step Solution:

  1. Resolve the Initial Velocity into Components:

    • Horizontal component, v0x=v0cosθv_{0x} = v_0 \cos \theta
    • Vertical component, v0y=v0sinθv_{0y} = v_0 \sin \theta

    Using θ=37.0\theta = 37.0^\circ: v0x=25.0cos37v_{0x} = 25.0 \cos 37^\circ v0y=25.0sin37v_{0y} = 25.0 \sin 37^\circ

  2. Calculate the Time of Flight: The time of flight TT can be found using the formula: T=2v0ygT = \frac{2 v_{0y}}{g} where g=9.8m/s2g = 9.8 \, \text{m/s}^2 is the acceleration due to gravity.

  3. Calculate the Horizontal Range: The horizontal range RR is given by: R=v0xTR = v_{0x} \cdot T

Solution:

Let's go through these calculations:

  1. Calculate v0xv_{0x} and v0yv_{0y}:

    • v0x=25.0cos3725.0×0.7986=19.965m/sv_{0x} = 25.0 \cos 37^\circ \approx 25.0 \times 0.7986 = 19.965 \, \text{m/s}
    • v0y=25.0sin3725.0×0.6018=15.045m/sv_{0y} = 25.0 \sin 37^\circ \approx 25.0 \times 0.6018 = 15.045 \, \text{m/s}
  2. Time of Flight TT: T=2×15.0459.83.07secondsT = \frac{2 \times 15.045}{9.8} \approx 3.07 \, \text{seconds}

  3. Horizontal Range RR: R=v0xT=19.965×3.0761.3metersR = v_{0x} \cdot T = 19.965 \times 3.07 \approx 61.3 \, \text{meters}

Answer:

The football travels approximately 61.3 meters horizontally.

Would you like more details on any of these steps or have any questions?


Related Questions:

  1. What would the horizontal range be if the initial velocity were 30 m/s?
  2. How does changing the launch angle affect the range of the projectile?
  3. How long does the football stay in the air (time of flight) if launched at a different angle?
  4. What is the maximum height the football reaches during its trajectory?
  5. How would air resistance alter the football's range?

Tip:

For projectile problems, breaking the initial velocity into horizontal and vertical components is essential for calculating both time of flight and range.

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Math Problem Analysis

Mathematical Concepts

Projectile Motion
Trigonometry

Formulas

Horizontal component of velocity: v_{0x} = v_0 cos θ
Vertical component of velocity: v_{0y} = v_0 sin θ
Time of flight: T = (2 v_{0y}) / g
Horizontal range: R = v_{0x} * T

Theorems

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Suitable Grade Level

Grade 10-12