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whats the horizontal component of Vector B

To calculate the horizontal component of **Vector B**, we use trigonometric functions.

Given:
- Magnitude of Vector B = **70 N**
- Direction of Vector B = **75° north of east**

Since the angle is north of east, it is measured from the positive x-axis. The horizontal component is found using the cosine function:

\[
\text{Horizontal Component of B} = B \cdot \cos(\theta)
\]

Where:
- \( B = 70 \) N
- \( \theta = 75^\circ \)

Now, calculating this:

\[
\text{Horizontal Component of B} = 70 \cdot \cos(75^\circ)
\]

Let me compute this.The horizontal component of Vector B is approximately **18.1 N**.

Would you like further explanation or have any other questions?

Here are some related questions to consider:
1. How is the vertical component of Vector B calculated?
2. What is the significance of the direction "north of east"?
3. How would the horizontal component change if the angle was south of east?
4. What is the total resultant vector if we add Vector A, B, and C?
5. How do we find the direction of the resultant vector?

**Tip:** Always double-check the angle’s reference direction (e.g., "north of east") to use the correct trigonometric function when calculating vector components.

What is the horizontal component of Vector C?

Learn how to calculate the horizontal component of Vector C using trigonometric functions. Given a vector with a magnitude of 95N and a direction of 87° west of north, we use cosine to resolve the vector into components.

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