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The question provided involves calculating the gravitational potential energy (Tenaga Keupayaan Graviti) of the Helios Prototype (HP01) at a height of 29,500 meters using the formula:

\[
E_p = mgh
\]

where:
- \( E_p \) is the gravitational potential energy,
- \( m \) is the mass of the object (600 kg),
- \( g \) is the acceleration due to gravity (10 m/s², as given),
- \( h \) is the height (29,500 meters).

Let's calculate the gravitational potential energy.The gravitational potential energy (Tenaga Keupayaan Graviti) of the Helios Prototype at a height of 29,500 meters is 177,000,000 Joules (or 177 million Joules).

Would you like further explanation on this or any other details?

Here are 5 related questions to explore further:
1. What is gravitational potential energy and how does it differ from kinetic energy?
2. How would the potential energy change if the height or mass were different?
3. How is gravitational potential energy applied in other fields, such as space exploration?
4. What happens to the energy as the Helios Prototype descends?
5. Can the gravitational potential energy formula be used for objects near Earth's surface at very high altitudes?

**Tip:** Gravitational potential energy is always dependent on both height and mass, meaning higher altitudes or heavier objects result in greater energy values.

Kira tenaga keupayaan graviti pesawat Helios Prototype (HP01) ini pada ketinggian 29,500m menggunakan rumus, Tenaga Keupayaan = mgh , (g = 10ms¯²)

Learn how to calculate the gravitational potential energy of the Helios Prototype (HP01) at a height of 29,500 meters using the formula E_p = mgh, where m = 600kg, g = 10ms¯². This problem focuses on the concept of gravitational potential energy in physics.

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