https://file.aiquickdraw.com/mathbot/file/1726110949275812vozyk.jpg

To solve the problem given in the image, we need to calculate the gravitational potential energy of the Helios Prototype (HP 01) at a height of 29,500 meters using the formula \( E_p = mgh \).

Here's the information we have:
- Mass (\( m \)) of the Helios Prototype (HP 01) = 600 kg
- Height (\( h \)) = 29,500 meters
- Acceleration due to gravity (\( g \)) = 10 m/s²

Using the formula \( E_p = mgh \):

\[ E_p = 600 \, \text{kg} \times 10 \, \text{m/s}^2 \times 29,500 \, \text{m} \]

Now, let's calculate the potential energy.

\[ E_p = 600 \times 10 \times 29,500 \]
\[ E_p = 6,000 \times 29,500 \]
\[ E_p = 177,000,000 \, \text{J} \]

So, the gravitational potential energy of the Helios Prototype (HP 01) at a height of 29,500 meters is 177,000,000 joules (or 177 MJ).

Do you want any more details or have any questions?

Here are some related questions you might find interesting:
1. What would be the gravitational potential energy at half this height?
2. How does the gravitational potential energy change if the mass of the object is doubled?
3. What is the potential energy if the height is increased to 40,000 meters?
4. How does the value of \( g \) (acceleration due to gravity) affect the potential energy?
5. What is the kinetic energy of the Helios Prototype if it falls from 29,500 meters to the ground without any energy loss?

**Tip:** Gravitational potential energy depends on the mass of the object, the height above the reference point, and the local gravitational field strength.

Kira tenaga keupayaan graviti pesawat Helios Prototype (HP 01) ini pada ketinggian 29,500m menggunakan rumus, Tenaga Keupayaan = mgh, (g = 10ms⁻²)

Learn how to calculate the gravitational potential energy of the Helios Prototype (HP 01) at a height of 29,500 meters using the formula E_p = mgh. This problem involves basic physics concepts suitable for students in Grades 9-11.

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