it takes 50oz of grass seed to seed 4000 feet squared of lawn. At this rate how much would be needed for 9600 feet squared of lawn?

To solve this, we will set up a proportion based on the given rate:

\[
\frac{50 \, \text{oz}}{4000 \, \text{ft}^2} = \frac{x \, \text{oz}}{9600 \, \text{ft}^2}
\]

Now, cross-multiply and solve for \( x \) (the amount of seed needed for 9600 square feet):

\[
50 \times 9600 = 4000 \times x
\]

\[
480000 = 4000x
\]

Now, divide both sides by 4000:

\[
x = \frac{480000}{4000} = 120 \, \text{oz}
\]

So, you would need **120 ounces** of grass seed for 9600 square feet of lawn.

Would you like more details, or do you have any questions?

Here are 5 related questions to explore further:
1. How much seed is needed for a 2000 square foot lawn?
2. How much lawn could you seed with 75 ounces of grass seed?
3. If you reduce the seed amount by 10%, how much would be needed for 9600 square feet?
4. How would the rate change if the lawn condition requires 25% more seed?
5. What if the lawn area is 12000 square feet? How much seed would be required?

**Tip:** When working with proportions, ensure that the units match on both sides of the equation for consistency.

It takes 50oz of grass seed to seed 4000 feet squared of lawn. At this rate, how much would be needed for 9600 feet squared of lawn?

Learn how to calculate the amount of grass seed needed for 9600 square feet of lawn using a proportional relationship. This problem involves setting up a proportion and solving for the unknown amount of seed, with a step-by-step guide. Suitable for students in Grades 6-8.

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