Tobias is at the Lucky-18 Mini Gold Course. He putts a golf ball up a hill (defined as the + direction) towards the hole.

If Tobias gives the ball an initial speed of 2.72 m/s and the ball slows at a constant rate of -0.629 m/s/s, what is the ball's velocity after 2.08 s? (Include a – sign if applicable.)

To find the velocity of the ball after 2.08 seconds, we can use the equation of motion that relates initial velocity, acceleration, and time:

\[
v = v_0 + at
\]

where:
- \( v \) is the final velocity,
- \( v_0 = 2.72 \, \text{m/s} \) is the initial velocity,
- \( a = -0.629 \, \text{m/s}^2 \) is the acceleration (negative because it’s slowing down),
- \( t = 2.08 \, \text{s} \) is the time.

Substituting the given values:

\[
v = 2.72 + (-0.629) \times 2.08
\]

Let's calculate the result.The velocity of the ball after 2.08 seconds is approximately \( 1.41 \, \text{m/s} \). 

Would you like further details or have any questions?

Here are some related questions you might find interesting:

1. What would the ball’s velocity be after 3 seconds?
2. How far does the ball travel in the first 2.08 seconds?
3. At what time will the ball come to a stop?
4. What is the ball's velocity if it starts moving downhill instead?
5. How would changing the initial speed affect the time it takes for the ball to stop?

**Tip:** Negative acceleration means the object is slowing down in the direction of motion.

Learn how to calculate the velocity of a golf ball after 2.08 seconds with a detailed physics solution. This problem involves kinematics and uniformly decelerated motion, using the equation of motion to find the final velocity of the ball. Suitable for high school students studying physics.

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