An x-ray photon with an energy of 600 keV has a frequency of

To find the frequency of an x-ray photon with an energy of 600 keV, we use the relationship between energy and frequency in quantum mechanics:

\[
E = h \cdot f
\]

Where:
- \(E\) is the energy of the photon,
- \(h\) is Planck's constant (\(6.626 \times 10^{-34} \, \text{J·s}\)),
- \(f\) is the frequency of the photon.

Since the energy is given in keV (kiloelectron volts), we need to convert it to joules. The conversion factor is:

\[
1 \, \text{eV} = 1.602 \times 10^{-19} \, \text{J}
\]

Thus, 600 keV is:

\[
600 \, \text{keV} = 600 \times 10^3 \, \text{eV} = 600 \times 10^3 \times 1.602 \times 10^{-19} \, \text{J} = 9.612 \times 10^{-14} \, \text{J}
\]

Now we can solve for the frequency:

\[
f = \frac{E}{h} = \frac{9.612 \times 10^{-14}}{6.626 \times 10^{-34}} \, \text{Hz}
\]

Let me calculate that for you.The frequency of the x-ray photon with an energy of 600 keV is approximately \(1.45 \times 10^{20}\) Hz.

Would you like further details on this calculation or have any questions?

Here are some related questions you might find interesting:
1. What is the wavelength of a photon with a frequency of \(1.45 \times 10^{20}\) Hz?
2. How is the energy of a photon related to its wavelength?
3. What is the energy of a visible light photon compared to an x-ray photon?
4. How does the energy of photons affect their interaction with matter?
5. How does the photoelectric effect relate to photon energy?

**Tip:** The higher the frequency of a photon, the higher its energy and ability to penetrate matter!

Learn how to calculate the frequency of an x-ray photon with an energy of 600 keV using Planck's formula. This detailed step-by-step solution involves quantum mechanics principles, energy conversion, and frequency calculations. Suitable for high school and college physics students.

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