To determine how long it takes her to reach the ground, we need to know two main things:

1. The height from which she is falling (or starting her descent).
2. The acceleration due to gravity, usually $g = 9.8 \, \text{m/s}^2$ (assuming the fall occurs near the Earth's surface and there's no air resistance).

The time $t$ it takes to reach the ground in free fall can be found using the following equation:

$h = \frac{1}{2}gt^2$

where:

• $h$ is the height from which she falls.
• $g$ is the acceleration due to gravity (approximately $9.8 \, \text{m/s}^2$).
• $t$ is the time taken to reach the ground.

We can rearrange the equation to solve for $t$:

$t = \sqrt{\frac{2h}{g}}$

If you provide the height $h$, I can calculate the exact time it takes her to reach the ground.

Would you like to proceed with this, or do you have additional details?

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Follow-up Questions:

1. What would the time be if the height were doubled?
2. How does air resistance affect the time taken to reach the ground?
3. How would the time differ on a planet with a different gravitational acceleration?
4. What is the significance of initial velocity in free fall calculations?
5. How would the time change if she were to jump up slightly before descending?

Tip: Always check units to ensure accuracy in physics problems!