Math Problem Statement

Solve for F13 using the formula Fn=(1+^5)n-(1-^5)n over 2n^5

Solution

The formula provided for FnF_n appears to be a variant of the closed-form expression for Fibonacci numbers, known as Binet's formula. However, the formula as written seems unclear due to the notation. The correct Binet's formula is:

Fn=15[(1+52)n(152)n]F_n = \frac{1}{\sqrt{5}} \left[ \left(\frac{1 + \sqrt{5}}{2}\right)^n - \left(\frac{1 - \sqrt{5}}{2}\right)^n \right]

We are tasked with finding F13F_{13}, so let's calculate it using the correct formula.

Step 1: Identify the constants

  • ϕ1=1+52\phi_1 = \frac{1 + \sqrt{5}}{2}
  • ϕ2=152\phi_2 = \frac{1 - \sqrt{5}}{2}

Step 2: Calculate ϕ113\phi_1^{13} and ϕ213\phi_2^{13}

Let's begin by calculating these powers.

Step 3: Apply the formula for F13F_{13}

F13=15(ϕ113ϕ213)F_{13} = \frac{1}{\sqrt{5}} \left(\phi_1^{13} - \phi_2^{13}\right)

Now, let’s compute it.

ϕ1=1+521.6180339887\phi_1 = \frac{1 + \sqrt{5}}{2} \approx 1.6180339887 ϕ2=1520.6180339887\phi_2 = \frac{1 - \sqrt{5}}{2} \approx -0.6180339887

So,

ϕ1131.618033988713521.025\phi_1^{13} \approx 1.6180339887^{13} \approx 521.025 ϕ213(0.6180339887)130.000025\phi_2^{13} \approx (-0.6180339887)^{13} \approx -0.000025

Now,

F13=15(521.025(0.000025))521.025+0.0000252.236067977521.0252.236067977233F_{13} = \frac{1}{\sqrt{5}} \left(521.025 - (-0.000025)\right) \approx \frac{521.025 + 0.000025}{2.236067977} \approx \frac{521.025}{2.236067977} \approx 233

Therefore,

F13=233F_{13} = 233

Would you like more details on the calculation process, or do you have any other questions?

Here are five related questions:

  1. How is Binet's formula derived from the Fibonacci sequence?
  2. Can Binet's formula be applied to negative indices of the Fibonacci sequence?
  3. What is the significance of the golden ratio (ϕ\phi) in Fibonacci numbers?
  4. How would you calculate F13F_{13} using a recursive method instead of Binet's formula?
  5. What are some real-world applications of Fibonacci numbers?

Tip: When dealing with Fibonacci numbers, Binet's formula offers a direct method to compute any Fibonacci number without the need for recursion.

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Math Problem Analysis

Mathematical Concepts

Fibonacci sequence
Binet's formula
Exponential growth

Formulas

Binet's formula for Fibonacci numbers

Theorems

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Suitable Grade Level

Advanced High School to College