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The problem asks to find the measure of a single exterior angle of a regular 11-gon.

The formula to find the exterior angle of a regular polygon is:

\[
\text{Exterior Angle} = \frac{360^\circ}{n}
\]

where \( n \) is the number of sides of the polygon. In this case, for an 11-sided polygon (11-gon):

\[
\text{Exterior Angle} = \frac{360^\circ}{11} \approx 32.73^\circ
\]

Rounding to the nearest tenth:

\[
\text{Exterior Angle} \approx 32.7^\circ
\]

Let me know if you'd like further details or have any questions!

Here are 5 related questions to consider:
1. What is the interior angle of a regular 11-gon?
2. How do you calculate the sum of all interior angles of any polygon?
3. What would be the exterior angle of a regular 15-gon?
4. How does the number of sides affect the size of the exterior angle in polygons?
5. What is the relationship between interior and exterior angles in a polygon?

**Tip:** The sum of the exterior angles for any polygon is always \(360^\circ\), regardless of the number of sides!

Find the measure of a single exterior angle of a regular 11-gon. If necessary, round to the nearest tenth.

Learn how to find the measure of a single exterior angle of a regular 11-gon using the formula: Exterior Angle = 360° / n. This detailed step-by-step solution shows the calculation and rounds to the nearest tenth. Perfect for students in Grades 8-10.

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