The image you provided contains a circuit and a question related to resistance.

The question asks for the equivalent resistance of a circuit that resembles a combination of resistors in series and parallel. From the structure of the circuit, it seems to involve two resistors in parallel, connected to another resistor in series. The goal is to determine the total or equivalent resistance for this configuration.

Let's break it down:

• There are two resistors with values $10 \, \Omega$ and $20 \, \Omega$ connected in parallel.
• This combination is then in series with a resistor of value $R$ (the resistor marked with $R$).

To find the equivalent resistance $R_{\text{eq}}$, we will:

1. Calculate the total resistance for the two resistors in parallel.
2. Add this to the series resistor.

Let's proceed with solving this step-by-step:

1. Resistors in Parallel: The formula for two resistors in parallel is: $\frac{1}{R_{\text{parallel}}} = \frac{1}{R_1} + \frac{1}{R_2}$ where $R_1 = 10 \, \Omega$ and $R_2 = 20 \, \Omega$.

2. Adding the Series Resistor: The total resistance $R_{\text{total}}$ is the sum of the parallel resistance and the series resistance $R$: $R_{\text{total}} = R_{\text{parallel}} + R$

Would you like me to proceed with the calculations, or do you have any specific values for $R$ to input?