Math Problem Statement
Calculate the energy (in kJ) needed to heat 75.3 g of butane from its liquid to gas phase without a change in temperature.
To calculate the answer, we need to know:
the temperature remains constant the butane boiling point of 0.0 °C the butane heat of vaporization is 22.4 kJ/mol the butane molar mass is 58.12 g/mol Kelvin temperature = 273.15 + Celsius temperature
Solution
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Math Problem Analysis
Mathematical Concepts
Stoichiometry
Phase Changes
Energy Calculations
Formulas
q = n × ΔHvap
n = mass / molar mass
Theorems
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Suitable Grade Level
Grades 10-12
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