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solve this. Hint: From the amount of heat required to convert a given mass of liquid water into steam, we can find the enthalpy of vaporization (Δ*H*vap) for 1 mole of water.

Conversion of 0.952 g of liquid water to steam at 100.0°C requires 2.12 kJ of heat. Calculate the molar enthalpy of evaporation of water at 100.0°C.

Learn how to calculate the molar enthalpy of evaporation for water at 100.0°C, given that converting 0.952 g of liquid water to steam requires 2.12 kJ of heat. This thermodynamics problem is suitable for college-level chemistry students and demonstrates unit conversion and enthalpy calculation.

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