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The problem asks how many days the family's emergency water supply (66 gallons) will last, given that:

- Adults use \( 4 \frac{1}{2} \) gallons per day
- Children use \( 3 \frac{3}{4} \) gallons per day

### Steps to solve:

1. Convert mixed numbers to improper fractions:
   - \( 4 \frac{1}{2} = \frac{9}{2} \) gallons for adults
   - \( 3 \frac{3}{4} = \frac{15}{4} \) gallons for children

2. To combine the water usage of adults and children per day, we need to find the least common denominator (LCD) of the two fractions:
   - LCD of 2 and 4 is 4.
   - Convert both fractions to have the same denominator:
     - \( \frac{9}{2} = \frac{18}{4} \) (for adults)
     - \( \frac{15}{4} \) (for children)

3. Add the daily water usage:
   \[
   \frac{18}{4} + \frac{15}{4} = \frac{33}{4} \text{ gallons per day}
   \]

4. Now, divide the total water supply by the daily water usage:
   \[
   \frac{66}{1} \div \frac{33}{4} = \frac{66}{1} \times \frac{4}{33} = \frac{264}{33} = 8 \text{ days}
   \]

### Conclusion:
The emergency water supply would last the family for 8 days.

Do you have any questions or would you like further details? 

Here are 5 related questions to expand on this problem:
1. What would happen if the family had 70 gallons of water instead of 66?
2. How would the result change if the adults needed 5 gallons per day?
3. How much water would be needed for 10 days at the current rate?
4. What would be the result if the children's water needs increased to 5 gallons per day?
5. How would this calculation change if the family had a second adult?

**Tip**: Always convert mixed numbers to improper fractions for easier calculations in such problems!

A family prepares an emergency kit for their home. The kit contains 66 gallons of drinking water. The family's daily drinking water needs are 4 1/2 gallons for the adults and 3 3/4 gallons for the children. For how many days would this emergency water supply last the family?

Learn how to calculate how long a 66-gallon emergency water supply will last for a family. This problem involves converting mixed numbers to improper fractions, adding daily water consumption, and dividing to find the number of days. Ideal for students in Grades 6-8.

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