A charge of +2×10^−6 C is placed in an electric field where the electric potential is 5000 V Calculate the electric potential energy of the charge in this field.

The electric potential energy (\( U \)) of a charge in an electric field is given by the formula:

\[
U = qV
\]

where:
- \( q \) is the charge,
- \( V \) is the electric potential.

Given:
- \( q = +2 \times 10^{-6} \, \text{C} \),
- \( V = 5000 \, \text{V} \).

Substituting these values into the formula:

\[
U = (2 \times 10^{-6} \, \text{C}) \times (5000 \, \text{V})
\]

\[
U = 10^{-5} \, \text{C} \cdot \text{V}
\]

\[
U = 0.01 \, \text{J}
\]

So, the electric potential energy of the charge in this field is \( 0.01 \, \text{J} \).

Would you like more details or have any questions? 

Here are some related questions:

1. What is the relationship between electric potential energy and electric potential?
2. How does the sign of the charge affect the potential energy?
3. What would happen to the potential energy if the charge were negative?
4. How does electric potential differ from electric field strength?
5. How does distance from a source charge affect electric potential?

**Tip:** The electric potential energy is dependent on both the magnitude and sign of the charge as well as the electric potential at the point where the charge is placed.

Learn how to calculate the electric potential energy of a charge (+2×10^−6 C) placed in an electric field where the electric potential is 5000 V. This problem involves using the formula U = qV and covers key concepts in electric potential energy and charge interactions. Suitable for students in Grades 10-12.

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