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The problem is written in Ukrainian and it translates to:

"Calculate the electric field strength at the point where a force of 0.4 mN acts on a charge of 2 nC."

We can use the formula for electric field strength \(E\) in terms of force \(F\) and charge \(q\):

\[
E = \frac{F}{q}
\]

Where:
- \( F = 0.4 \, \text{mN} = 0.4 \times 10^{-3} \, \text{N} \)
- \( q = 2 \, \text{nC} = 2 \times 10^{-9} \, \text{C} \)

Let me calculate this for you.The electric field strength at the point where a force of 0.4 mN acts on a charge of 2 nC is \( 200,000 \, \text{N/C} \) or \( 2 \times 10^5 \, \text{N/C} \).

Would you like further details or have any other questions?

Here are five related questions to explore:
1. What is the relationship between electric field and force?
2. How does the electric field change if the charge is doubled?
3. What are the units of electric field strength and why?
4. How is the direction of the electric field related to the direction of the force?
5. Can we calculate the electric field due to a point charge in a vacuum?

**Tip:** Remember that the electric field strength is directly proportional to the force acting on the charge and inversely proportional to the charge.

Обчисліть напруженість поля в точці, у якій на заряд 2 нКл діє електрична сила 0,4 мН.

Learn how to calculate the electric field strength at a point where a force of 0.4 mN acts on a 2 nC charge. This problem covers key concepts in electrostatics and uses the formula E = F / q. Suitable for high school students in Grades 10-12.

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