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The problem states that the distance to a thunderstorm is calculated by the number of seconds between seeing the lightning and hearing the thunder, divided by 5.

Given:
- A lightning flash is seen at 9:10:00.
- Thunder is heard 15 seconds later.

Let's calculate the distance:

1. The time difference between seeing the lightning and hearing the thunder is 15 seconds.
2. According to the rule, distance in miles = time in seconds / 5.

Thus, the distance to the thunderstorm is:

\[
\text{Distance} = \frac{15 \text{ seconds}}{5} = 3 \text{ miles}
\]

So, the correct answer is **3 miles**.

Would you like more details or have any questions?

Here are some related questions to consider:
1. How does the speed of sound affect the calculation of the thunderstorm's distance?
2. What would the distance be if the time between lightning and thunder was 20 seconds?
3. Why is the distance divided by 5 in this specific calculation?
4. How would the distance calculation change if the speed of sound varied?
5. What other methods could be used to estimate the distance of a thunderstorm?

**Tip:** Always double-check the time difference in these types of problems, as accuracy is crucial for the correct distance calculation.

The distance to a thunderstorm is the number of seconds between seeing the lightning and hearing the thunder, divided by 5. A lightning flash at 9:10:00 is followed by thunder 15 seconds later. How far away is the thunderstorm?

Learn how to calculate the distance to a thunderstorm using the time difference between seeing lightning and hearing thunder. Given a 15-second delay, discover the simple formula for distance calculation. Perfect for students in Grades 5-7.

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