Math Problem Statement

Find the distance (in ft) traveled in 10 seconds by an object traveling at a velocity of v(t) = 20 + 5 cos(t) feet per second.

Solution

To find the distance traveled by an object over a given time interval when its velocity v(t)v(t) is known, we need to compute the definite integral of the velocity function over that time interval.

Given the velocity function: v(t)=20+5cos(t)v(t) = 20 + 5 \cos(t)

We want to find the distance traveled over the time interval from t=0t = 0 to t=10t = 10 seconds. The distance traveled is given by:

Distance=010v(t)dt=010(20+5cos(t))dt\text{Distance} = \int_{0}^{10} v(t) \, dt = \int_{0}^{10} (20 + 5 \cos(t)) \, dt

Step-by-Step Solution

  1. Separate the Integral:

010(20+5cos(t))dt=01020dt+0105cos(t)dt\int_{0}^{10} (20 + 5 \cos(t)) \, dt = \int_{0}^{10} 20 \, dt + \int_{0}^{10} 5 \cos(t) \, dt

  1. Compute Each Integral:
  • The first integral is straightforward:

[ \int_{0}^{10} 20 , dt = 20t \Big|_{0}^{10} = 20