Math Problem Statement

The downstream speed of boat A is equal to the upstream speed of boat B. Boat A covers M km upstream in t hours and boat B covers the same distance downstream in (t-4) hours. If the speed of (in still water) boat A and boat B is 14 km/hr and 22 km/hr respectively, then find the value of M.

a) 72

b) 65

c) 80

d) 94

e) 105

Solution

Let's denote the variables as follows:

  • uAu_A and dAd_A are the upstream and downstream speeds of boat A, respectively.
  • uBu_B and dBd_B are the upstream and downstream speeds of boat B, respectively.
  • vv is the speed of the stream (current).
  • MM is the distance covered by both boats upstream and downstream.
  • tt is the time taken by boat A to cover MM km upstream.
  • t4t - 4 is the time taken by boat B to cover MM km downstream.

Given:

  • The speed of boat A in still water is 1414 km/hr.
  • The speed of boat B in still water is 2222 km/hr.
  • The downstream speed of boat A is equal to the upstream speed of boat B, i.e., dA=uBd_A = u_B.

Step 1: Express upstream and downstream speeds

  • For boat A:

    • Upstream speed: uA=14vu_A = 14 - v
    • Downstream speed: dA=14+vd_A = 14 + v
  • For boat B:

    • Upstream speed: uB=22vu_B = 22 - v
    • Downstream speed: dB=22+vd_B = 22 + v

Step 2: Use the given condition dA=uBd_A = u_B

Given dA=uBd_A = u_B: 14+v=22v14 + v = 22 - v Solving for vv: 2v=22142v = 22 - 14 2v=8v=4 km/hr2v = 8 \quad \Rightarrow \quad v = 4 \text{ km/hr}

Step 3: Use the time and distance relationships

Now that we know v=4v = 4 km/hr, we can calculate the upstream and downstream speeds:

  • For boat A:

    • uA=144=10u_A = 14 - 4 = 10 km/hr
    • dA=14+4=18d_A = 14 + 4 = 18 km/hr
  • For boat B:

    • uB=224=18u_B = 22 - 4 = 18 km/hr
    • dB=22+4=26d_B = 22 + 4 = 26 km/hr

Step 4: Set up the distance equations

For boat A (upstream): M=uA×t=10tM = u_A \times t = 10t

For boat B (downstream): M=dB×(t4)=26(t4)M = d_B \times (t - 4) = 26(t - 4)

Step 5: Equate the two expressions for MM

Since both equations represent MM: 10t=26(t4)10t = 26(t - 4)

Step 6: Solve for tt

Expanding and solving for tt: 10t=26t10410t = 26t - 104 104=26t10t104 = 26t - 10t 104=16t104 = 16t t=10416=6.5 hourst = \frac{104}{16} = 6.5 \text{ hours}

Step 7: Find the value of MM

Substitute t=6.5t = 6.5 into the equation M=10tM = 10t: M=10×6.5=65 kmM = 10 \times 6.5 = 65 \text{ km}

Thus, the value of MM is 65\boxed{65}.

Would you like more details or have any questions? Here are 5 related questions for you to consider:

  1. What would be the distance MM if the speed of the stream was different?
  2. How does the time taken by boat B downstream change with different values of vv?
  3. Can we determine the time difference if the distances were different for both boats?
  4. What would happen if the speed of one boat in still water was reduced?
  5. How can we use these equations to solve for other related boat speed problems?

Tip: Always check if there's a direct relationship between upstream and downstream speeds that can simplify the problem-solving process.

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Math Problem Analysis

Mathematical Concepts

Speed, Distance, Time Problems
Relative Motion

Formulas

Distance = Speed × Time

Theorems

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Suitable Grade Level

High School