Math Problem Statement

Find the distance between the two points rounding to the nearest tenth: (6, -8) and (1, 4)

Solution

The problem asks for the distance between two points (6,8)(6, -8) and (1,4)(1, 4). We can calculate the distance using the distance formula:

d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Where (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) are the coordinates of the two points. Substituting the given points (6,8)(6, -8) and (1,4)(1, 4):

d=(16)2+(4+8)2d = \sqrt{(1 - 6)^2 + (4 + 8)^2} d=(5)2+(12)2d = \sqrt{(-5)^2 + (12)^2} d=25+144d = \sqrt{25 + 144} d=169=13d = \sqrt{169} = 13

So, the distance between the two points is 13.

Would you like further details on this, or do you have any other questions?

Here are 5 related questions you might find useful:

  1. How do you find the midpoint between two points?
  2. What is the formula for finding the slope between two points?
  3. Can you explain how the Pythagorean theorem is related to the distance formula?
  4. What are some applications of the distance formula in real life?
  5. How can you extend the distance formula to 3D coordinates?

Tip: Always remember to check for sign errors when subtracting coordinates to avoid calculation mistakes.

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Math Problem Analysis

Mathematical Concepts

Coordinate Geometry
Distance Between Two Points

Formulas

Distance Formula: d = √((x2 - x1)^2 + (y2 - y1)^2)

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 8-10