https://file.aiquickdraw.com/mathbot/file/1727444305928w3x1jcj6.jpg

The problem in the image asks to find the distance between two points \( (6, -8) \) and \( (1, 4) \), rounding the result to the nearest tenth if necessary.

To solve this, we use the distance formula:

\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]

Where:
- \( (x_1, y_1) = (6, -8) \)
- \( (x_2, y_2) = (1, 4) \)

Let's calculate the distance:

\[
d = \sqrt{(1 - 6)^2 + (4 + 8)^2}
= \sqrt{(-5)^2 + (12)^2}
= \sqrt{25 + 144}
= \sqrt{169}
= 13
\]

Thus, the distance between the two points is \( 13 \). No rounding is necessary, as it is already an integer.

Do you have any questions about this? Would you like more details on any part of the solution?

Here are 5 related questions for further practice:
1. Find the distance between \( (3, 7) \) and \( (-1, 4) \).
2. What is the distance between \( (-2, -3) \) and \( (4, 6) \)?
3. Calculate the distance between \( (0, 0) \) and \( (5, 12) \).
4. How do you derive the distance formula from the Pythagorean theorem?
5. What would be the coordinates of the midpoint between \( (6, -8) \) and \( (1, 4) \)?

**Tip**: Always ensure you subtract coordinates in the same order (e.g., \( x_2 - x_1 \) and \( y_2 - y_1 \)) to avoid sign errors.

Find the distance between the two points rounding to the nearest tenth if necessary: (6, -8) and (1, 4).

Learn how to calculate the distance between the points (6, -8) and (1, 4) using the distance formula. This detailed step-by-step guide demonstrates how to apply the Pythagorean theorem in coordinate geometry. Suitable for students in Grades 8-10.

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