Math Problem Statement

What is the distance, to the nearest tenth, between the points (4, 3) and (9, 5)?  

Solution

To find the distance between the points (4,3)(4, 3) and (9,5)(9, 5), we can use the distance formula:

d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Given points:

  • (x1,y1)=(4,3)(x_1, y_1) = (4, 3)
  • (x2,y2)=(9,5)(x_2, y_2) = (9, 5)

Plugging in the values:

d=(94)2+(53)2=52+22=25+4=29d = \sqrt{(9 - 4)^2 + (5 - 3)^2} = \sqrt{5^2 + 2^2} = \sqrt{25 + 4} = \sqrt{29}

Now, approximate 29\sqrt{29}:

295.385\sqrt{29} \approx 5.385

Rounding to the nearest tenth:

d5.4d \approx 5.4

So, the distance between the points (4,3)(4, 3) and (9,5)(9, 5) is approximately 5.4 units.

Would you like to explore further details or concepts related to this problem?


Here are 5 related questions:

  1. How do you determine the midpoint between two points?
  2. What is the equation of a circle with a center at (4,3)(4, 3) and radius equal to the distance calculated?
  3. How can you calculate the slope of the line passing through these two points?
  4. What would be the distance if one of the points was (0,0)(0, 0)?
  5. How can you use the distance formula to verify if three points are collinear?

Tip: Always double-check your calculations, especially when dealing with square roots, to ensure accuracy when rounding.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Coordinate Geometry
Distance Formula
Square Roots

Formulas

Distance formula: d = sqrt((x2 - x1)^2 + (y2 - y1)^2)

Theorems

-

Suitable Grade Level

Grades 7-9