Math Problem Statement

Find the distance between the points (1,3) and (4,7).

Solution

To find the distance between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) in a plane, we use the distance formula:

d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Given points:

  • Point 1: (1,3)(1, 3)
  • Point 2: (4,7)(4, 7)

Calculation:

  1. Subtract the xx-coordinates: x2x1=41=3x_2 - x_1 = 4 - 1 = 3
  2. Subtract the yy-coordinates: y2y1=73=4y_2 - y_1 = 7 - 3 = 4
  3. Square the differences: (x2x1)2=32=9,(y2y1)2=42=16(x_2 - x_1)^2 = 3^2 = 9, \quad (y_2 - y_1)^2 = 4^2 = 16
  4. Add the squares: 9+16=259 + 16 = 25
  5. Take the square root: d=25=5d = \sqrt{25} = 5

Final Answer:

The distance between the points (1,3)(1, 3) and (4,7)(4, 7) is 5\mathbf{5}.

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Related Questions:

  1. How do you derive the distance formula?
  2. What is the distance between (2,5)(-2, 5) and (3,1)(3, -1)?
  3. Can this method be used for points in 3D space?
  4. What is the midpoint of the points (1,3)(1, 3) and (4,7)(4, 7)?
  5. How does this formula relate to the Pythagorean theorem?

Tip: Always label points clearly in coordinate geometry problems to avoid confusion.

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Math Problem Analysis

Mathematical Concepts

Coordinate Geometry
Distance Formula

Formulas

d = sqrt((x2 - x1)^2 + (y2 - y1)^2)

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 7-9