Jackson is packing a lunch box to take to school. Jackson can make 8 kinds of sandwiches, and there are 3 kinds of fruit in the house. There are 2 flavors of juice boxes in the refrigerator. Finally, there are 5 desserts in the house. Assuming Jackson packs one of each item, how many different lunches can he pack?


To find how many different lunches Jackson can pack, we need to multiply the number of choices for each item:

- Jackson has **8 sandwich options**.
- He has **3 fruit options**.
- There are **2 juice box flavors**.
- Finally, there are **5 dessert options**.

Since Jackson picks one of each item, we multiply these options together:

\[
8 \times 3 \times 2 \times 5 = 240
\]

Thus, Jackson can pack **240 different lunches**.

Would you like more details, or do you have any other questions?

Here are 5 related questions for further practice:
1. What if Jackson had 4 kinds of fruit instead of 3? How many different lunches could he pack?
2. What if Jackson wanted to pack two desserts instead of one? How many different combinations would he have then?
3. If Jackson could choose not to pack a fruit, how many combinations would he have?
4. If Jackson decided to pack 2 sandwiches, how many combinations could he make?
5. What if Jackson had no dessert options? How many different lunches could he pack?

**Tip:** When calculating combinations of independent choices, simply multiply the number of options for each item.

Explore how many different lunch combinations Jackson can pack using sandwiches, fruits, juice flavors, and desserts. Learn the multiplication principle in combinatorics through this math problem. Suitable for Grades 4-6.

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