Math Problem Statement

Find the difference quotient of f; that is find (f(x + h) - f(x)) / h, h ≠ 0, for the function f(x) = √(x - 12). Hint: Rationalize the numerator.

Solution

The problem asks for the difference quotient of the function f(x)=x12f(x) = \sqrt{x - 12}, and gives the formula:

f(x+h)f(x)h,h0.\frac{f(x+h) - f(x)}{h}, \quad h \neq 0.

Let's solve this step by step:

Step 1: Write the difference quotient

We need to substitute the function f(x)=x12f(x) = \sqrt{x - 12} into the difference quotient formula:

f(x+h)f(x)h=(x+h)12x12h.\frac{f(x+h) - f(x)}{h} = \frac{\sqrt{(x+h) - 12} - \sqrt{x - 12}}{h}.

This simplifies to:

x+h12x12h.\frac{\sqrt{x + h - 12} - \sqrt{x - 12}}{h}.

Step 2: Rationalize the numerator

To simplify this expression, we multiply the numerator and denominator by the conjugate of the numerator:

Multiply by x+h12+x12x+h12+x12.\text{Multiply by } \frac{\sqrt{x + h - 12} + \sqrt{x - 12}}{\sqrt{x + h - 12} + \sqrt{x - 12}}.

This gives:

(x+h12x12)(x+h12+x12)h(x+h12+x12).\frac{\left( \sqrt{x + h - 12} - \sqrt{x - 12} \right) \left( \sqrt{x + h - 12} + \sqrt{x - 12} \right)}{h \left( \sqrt{x + h - 12} + \sqrt{x - 12} \right)}.

Using the difference of squares formula:

(ab)(a+b)=a2b2,(a - b)(a + b) = a^2 - b^2,

we get:

(x+h12)(x12)h(x+h12+x12).\frac{(x + h - 12) - (x - 12)}{h \left( \sqrt{x + h - 12} + \sqrt{x - 12} \right)}.

Step 3: Simplify the numerator

Simplifying the expression inside the numerator:

(x+h12)(x12)=x+h12x+12=h.(x + h - 12) - (x - 12) = x + h - 12 - x + 12 = h.

So the expression becomes:

hh(x+h12+x12).\frac{h}{h \left( \sqrt{x + h - 12} + \sqrt{x - 12} \right)}.

Step 4: Cancel hh

Now we can cancel hh from the numerator and denominator:

1x+h12+x12.\frac{1}{\sqrt{x + h - 12} + \sqrt{x - 12}}.

Final Answer:

The simplified form of the difference quotient is:

1x+h12+x12.\frac{1}{\sqrt{x + h - 12} + \sqrt{x - 12}}.

Would you like more details or have any questions?

Here are some related questions:

  1. What is the purpose of rationalizing the numerator in the difference quotient?
  2. How does the difference quotient relate to the derivative?
  3. What happens if you don’t cancel out hh properly?
  4. Can the difference quotient be applied to functions other than square roots?
  5. How does this formula change if the function is f(x)=x+12f(x) = \sqrt{x + 12}?

Tip: When simplifying a difference quotient involving square roots, rationalizing the numerator is key to eliminating square roots and making further simplifications easier.

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Math Problem Analysis

Mathematical Concepts

Calculus
Difference Quotients
Square Roots
Rationalizing the Numerator

Formulas

Difference Quotient: (f(x+h) - f(x)) / h
Rationalization: (a - b)(a + b) = a^2 - b^2

Theorems

Difference of squares

Suitable Grade Level

Grades 11-12