Math Problem Statement

Determine the difference quotient f(x+h)-f(x)/h. f(x)=x^2-10x

Solution

To find the difference quotient f(x+h)f(x)h\frac{f(x+h) - f(x)}{h}, we'll follow these steps:

Step 1: Define f(x)f(x)

Given: f(x)=x210xf(x) = x^2 - 10x

Step 2: Calculate f(x+h)f(x+h)

We need to substitute x+hx+h into the function f(x)f(x): f(x+h)=(x+h)210(x+h)f(x+h) = (x+h)^2 - 10(x+h)

Expanding: f(x+h)=(x2+2xh+h2)10(x+h)f(x+h) = (x^2 + 2xh + h^2) - 10(x + h) f(x+h)=x2+2xh+h210x10hf(x+h) = x^2 + 2xh + h^2 - 10x - 10h

Step 3: Compute f(x+h)f(x)f(x+h) - f(x)

Now, subtract f(x)f(x) from f(x+h)f(x+h): f(x+h)f(x)=(x2+2xh+h210x10h)(x210x)f(x+h) - f(x) = (x^2 + 2xh + h^2 - 10x - 10h) - (x^2 - 10x)

Simplify: f(x+h)f(x)=x2+2xh+h210x10hx2+10xf(x+h) - f(x) = x^2 + 2xh + h^2 - 10x - 10h - x^2 + 10x f(x+h)f(x)=2xh+h210hf(x+h) - f(x) = 2xh + h^2 - 10h

Step 4: Divide by hh

Now, divide the result by hh: f(x+h)f(x)h=2xh+h210hh\frac{f(x+h) - f(x)}{h} = \frac{2xh + h^2 - 10h}{h}

Simplify: f(x+h)f(x)h=2x+h10\frac{f(x+h) - f(x)}{h} = 2x + h - 10

Final Answer:

The difference quotient is: f(x+h)f(x)h=2x+h10\frac{f(x+h) - f(x)}{h} = 2x + h - 10

Do you have any questions, or would you like more details?

Here are 5 related questions to expand on this concept:

  1. How does the difference quotient relate to the derivative of a function?
  2. What happens to the difference quotient as hh approaches 0?
  3. Can you compute the derivative of f(x)=x210xf(x) = x^2 - 10x using limits?
  4. How would the difference quotient change if the function were f(x)=x310xf(x) = x^3 - 10x?
  5. What is the geometric interpretation of the difference quotient?

Tip: The difference quotient is a key concept for understanding the derivative, which measures the rate of change of a function.

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Math Problem Analysis

Mathematical Concepts

Difference Quotient
Algebra
Functions
Polynomials

Formulas

Difference quotient formula: (f(x+h) - f(x)) / h
Polynomial expansion: (x+h)^2 = x^2 + 2xh + h^2

Theorems

Basic principles of polynomial functions

Suitable Grade Level

Grades 9-12