Math Problem Statement
One method for determining the depth of a well is to drop a stone into it and then measure the time it takes until the splash is heard. If d is the depth of the well (in feet) and t1 the time (in seconds) it takes for the stone to fall, then d = 16t12, so t1 =
d /4. Now if t2 is the time it takes for the sound to travel back up, then d = 1090t2 because the speed of sound is 1090 ft/s. So t2 = d/1090. Thus, the total time elapsed between dropping the stone and hearing the splash is t1 + t2 =
d 4 + d 1090 . How deep is the well if this total time is 5 s? (See the following figure. Round your answer to one decimal place.)
Solution
We are tasked with determining the depth of a well, given that the total time between dropping a stone and hearing the splash is 5 seconds. The total time is the sum of two components:
- is the time it takes for the stone to fall down the well.
- is the time it takes for the sound to travel back up the well.
We are provided with the following relationships:
- The time for the stone to fall is .
- The time for the sound to travel back is .
The total time elapsed is the sum of these two times: We are also given that the total time is 5 seconds, so:
Step 1: Combine the terms with a common denominator
To combine the fractions, we find a common denominator. The least common denominator between 4 and 1090 is 4360. Rewriting both fractions:
Now we can combine the fractions:
Step 2: Solve for
Now, multiply both sides of the equation by 4360 to eliminate the denominator:
Now, divide both sides by 1094:
Final Answer:
The depth of the well is approximately feet.
Would you like more details or clarifications on any part of the solution?
Here are 5 related questions to further your understanding:
- What assumptions are made in this problem about the effect of air resistance?
- How would the solution change if the speed of sound was different, such as in warmer or colder air?
- What formula would apply if the well were on a different planet with a different gravitational constant?
- How would you solve this if the total time was not 5 seconds, but another value?
- How does the speed of sound in water compare to that in air, and how would this affect the calculation if the splash occurred underwater?
Tip: Always pay attention to units, especially when mixing speeds (like sound) and distances (like depth), as they must be consistent to avoid errors!
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Math Problem Analysis
Mathematical Concepts
Algebra
Fraction Addition
Physics (Kinematics)
Units Conversion
Formulas
d = 16t1^2
t1 = d/4
t2 = d/1090
t1 + t2 = d/4 + d/1090
Theorems
-
Suitable Grade Level
Grades 10-12
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