To find the depth of the well, we use the equation for displacement under constant acceleration:

$d = v_0 t + \frac{1}{2} a t^2$

Where:

• $v_0 = 4.19 \, \text{m/s}$ is the initial velocity,
• $t = 1.07 \, \text{seconds}$ is the time,
• $a = 9.81 \, \text{m/s}^2$ is the acceleration due to gravity.

Now, calculating step by step.

1. $v_0 t = 4.19 \times 1.07 = 4.4833$
2. $\frac{1}{2} a t^2 = 0.5 \times 9.81 \times (1.07)^2 = 5.61227585$

Now, summing them up:

$d = 4.4833 + 5.61227585 = 10.09557585$

Final result: 10.09