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	What is the value of current I1?


I_1=5V/Req=5V/110KΩ=4.54×10^(-5) Amps=45.45microAmps=45.45μA



	What is the voltage drop over R1?






	What is the voltage drop over R2?



The circuit shown consists of a 5V DC power source and two resistors, \( R_1 = 10 \, \text{k}\Omega \) and \( R_2 = 100 \, \text{k}\Omega \), connected in series. Let's calculate the quantities step by step.

### 1. Total Equivalent Resistance (\( R_{\text{eq}} \)):
For resistors in series, the equivalent resistance is the sum of the individual resistances:
\[
R_{\text{eq}} = R_1 + R_2 = 10 \, \text{k}\Omega + 100 \, \text{k}\Omega = 110 \, \text{k}\Omega
\]

### 2. Current \( I_1 \):
Using Ohm's Law \( I = \frac{V}{R} \), the current \( I_1 \) through the series circuit is:
\[
I_1 = \frac{V_{\text{total}}}{R_{\text{eq}}} = \frac{5 \, \text{V}}{110 \, \text{k}\Omega} = \frac{5}{110 \times 10^3} \, \text{A} \approx 45.45 \, \mu \text{A}
\]

### 3. Voltage Drop Across \( R_1 \):
The voltage drop across \( R_1 \) is given by Ohm's Law:
\[
V_{R_1} = I_1 \times R_1 = 45.45 \, \mu \text{A} \times 10 \, \text{k}\Omega = 45.45 \times 10^{-6} \, \text{A} \times 10 \times 10^3 \, \Omega = 0.4545 \, \text{V}
\]

### 4. Voltage Drop Across \( R_2 \):
Similarly, the voltage drop across \( R_2 \) is:
\[
V_{R_2} = I_1 \times R_2 = 45.45 \, \mu \text{A} \times 100 \, \text{k}\Omega = 45.45 \times 10^{-6} \, \text{A} \times 100 \times 10^3 \, \Omega = 4.545 \, \text{V}
\]

### Summary of Results:
- Current \( I_1 = 45.45 \, \mu \text{A} \)
- Voltage drop across \( R_1 = 0.4545 \, \text{V} \)
- Voltage drop across \( R_2 = 4.545 \, \text{V} \)

Let me know if you'd like more details or have any questions!

Here are 5 related questions to deepen your understanding:
1. What happens to the current if we reduce \( R_1 \) to 5 kΩ?
2. How would the voltage drops change if the total voltage increased to 10V?
3. What would the current be if \( R_2 \) were removed from the circuit?
4. How does increasing the resistance of \( R_2 \) affect the current in the circuit?
5. Can you calculate the power dissipated by \( R_1 \) and \( R_2 \)?

**Tip:** In a series circuit, the current is the same through all components, but the voltage drops across each resistor depend on its resistance.

What is the value of current I1? What is the voltage drop over R1? What is the voltage drop over R2?

Learn how to calculate the current and voltage drops in a series circuit with a 5V DC source and two resistors of 10kΩ and 100kΩ. The total current, I1, is determined using Ohm's Law, and voltage drops are calculated across each resistor. Suitable for students in Grades 9-12.

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