An electric shower has a power rating of 9.0 kW (9,000 W). If it is connected to the mains supply of

230 V, what current flows through the shower heater?

To find the current flowing through the shower heater, we can use **Ohm's Law** in the context of electrical power:

\[
P = IV
\]

Where:
- \( P \) is the power (in watts, W),
- \( I \) is the current (in amperes, A),
- \( V \) is the voltage (in volts, V).

Rearranging the formula to solve for current:

\[
I = \frac{P}{V}
\]

Now, plug in the values:
- \( P = 9000 \, \text{W} \)
- \( V = 230 \, \text{V} \)

\[
I = \frac{9000 \, \text{W}}{230 \, \text{V}} = 39.13 \, \text{A}
\]

So, the current flowing through the shower heater is approximately **39.13 A**.

Would you like more details on how this calculation relates to electrical systems, or do you have any questions?

Here are five related questions to explore further:
1. What is the significance of current in an electrical circuit?
2. How does power rating affect the safety of household electrical devices?
3. What would happen if the mains supply voltage were lower than 230 V?
4. How is electrical power converted to heat in appliances like electric showers?
5. What types of circuit breakers are used to handle high current devices like electric showers?

**Tip:** Always ensure the wiring and circuit breakers are rated to handle the current of high-power devices to avoid overloading the system.

An electric shower has a power rating of 9.0 kW (9,000 W). If it is connected to the mains supply of 230 V, what current flows through the shower heater?

Learn how to calculate the current flowing through a 9 kW electric shower connected to a 230V mains supply. Using Ohm's Law, this problem demonstrates key electrical concepts and formulas, ideal for students in Grades 9-12.

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