Math Problem Statement

What is the height, volume, or surface area of a right circular cone with a slant height of 8 inches and a base radius of 4 inches?

Solution

The image you've provided shows a right circular cone, where:

  • The slant height is 8in8 \, \text{in},
  • The radius of the base is 4in4 \, \text{in}.

To solve any questions regarding this cone (such as finding the volume, surface area, or height), the relevant formulas are:

  1. Height of the cone hh (which we can find using the Pythagorean theorem).
  2. Volume: V=13πr2hV = \frac{1}{3} \pi r^2 h
  3. Surface area (both lateral and total):
    • Lateral surface area: Alateral=πrlA_{\text{lateral}} = \pi r l where ll is the slant height.
    • Total surface area: Atotal=πr(r+l)A_{\text{total}} = \pi r (r + l)

Let's first find the height hh using the Pythagorean theorem, where hh, rr, and ll form a right triangle: h2+r2=l2h^2 + r^2 = l^2 h2+42=82h^2 + 4^2 = 8^2 h2+16=64h^2 + 16 = 64 h2=6416=48h^2 = 64 - 16 = 48 h=486.93inh = \sqrt{48} \approx 6.93 \, \text{in}

Now, you can use this height to calculate other properties like the volume or surface area. Would you like to calculate the volume, surface area, or explore more details?

Follow-up Questions:

  1. What is the total surface area of this cone?
  2. What is the volume of the cone using the height calculated?
  3. How does changing the radius affect the volume of the cone?
  4. What would the lateral surface area be if the slant height were doubled?
  5. How would the height change if the slant height was increased to 10 inches?

Tip:

When solving for geometric properties of a cone, always ensure to use the correct height for volume calculations, not the slant height.

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Math Problem Analysis

Mathematical Concepts

Geometry
Volume
Surface Area
Pythagorean Theorem

Formulas

Volume: V = (1/3) * π * r^2 * h
Lateral Surface Area: A_lateral = π * r * l
Total Surface Area: A_total = π * r * (r + l)
Pythagorean Theorem: h^2 + r^2 = l^2

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 9-12