A chemist prepares a solution of mercury(I) chloride

Hg2Cl2

by measuring out

0.00124μmol

of mercury(I) chloride into a

400.mL

volumetric flask and filling the flask to the mark with water.

Calculate the concentration in

/mmolL

of the chemist's mercury(I) chloride solution. Round your answer to

3

significant digits.

To find the concentration of the mercury(I) chloride (Hg₂Cl₂) solution in mmol/L, we can follow these steps:

### Step 1: Convert µmol to mmol
We are given the amount of mercury(I) chloride in **µmol** (0.00124 µmol). To convert µmol to mmol:
\[
1 \, \mu mol = 10^{-3} \, mmol
\]
So:
\[
0.00124 \, \mu mol = 0.00124 \times 10^{-3} \, mmol = 1.24 \times 10^{-6} \, mmol
\]

### Step 2: Convert the volume from mL to L
The volume of the solution is given as **400 mL**. To convert this to liters:
\[
1 \, L = 1000 \, mL
\]
Thus:
\[
400 \, mL = \frac{400}{1000} \, L = 0.400 \, L
\]

### Step 3: Calculate the concentration in mmol/L
The concentration \( C \) in mmol/L is calculated by dividing the amount of substance in mmol by the volume in liters:
\[
C = \frac{\text{amount of substance in mmol}}{\text{volume in L}}
\]
Substituting the values:
\[
C = \frac{1.24 \times 10^{-6} \, mmol}{0.400 \, L} = 3.10 \times 10^{-6} \, mmol/L
\]

### Final Answer:
The concentration of the mercury(I) chloride solution is:
\[
\boxed{3.10 \times 10^{-6} \, mmol/L}
\]

Do you want more details or have any questions?

---

Here are 5 related questions:
1. How do you convert molarity to other concentration units?
2. What is the significance of significant figures in concentration calculations?
3. Can you explain how to prepare a solution of a given concentration from a stock solution?
4. What is the molecular weight of Hg₂Cl₂ and how would you calculate moles from grams?
5. How would dilution affect the concentration of a solution?

**Tip:** Always ensure that your units are consistent when performing calculations, especially when converting between µmol, mmol, and mol.

A chemist prepares a solution of mercury(I) chloride (Hg2Cl2) by measuring out 0.00124 μmol of mercury(I) chloride into a 400 mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mmol/L of the chemist's mercury(I) chloride solution. Round your answer to 3 significant digits.

Learn how to calculate the concentration of a mercury(I) chloride (Hg₂Cl₂) solution by converting 0.00124 μmol to mmol and dividing by the volume of 400 mL, yielding a result of 3.10 × 10^-6 mmol/L. This problem involves unit conversion and concentration formulas, suitable for undergraduate chemistry students.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation