A drinking water treatment plant softens 21000000 m3m3 per year by dosing 1.14 mmol/Lmmol/L Ca(OH)2Ca(OH)2.
Molar mass of Ca(OH)2Ca(OH)2 is 74 g/mol.g/mol.

Calculate the amount of Ca(OH)2Ca(OH)2 dosed per in kton per year.




kton/yearkton/year, with 0 decimals

To calculate the amount of calcium hydroxide \(\text{Ca(OH)}_2\) dosed per year in kiloton (kton), we'll break it down step by step.

### Given:
- Volume of water treated per year: \( 21,000,000 \, \text{m}^3 \, \text{per year} \)
- Concentration of \(\text{Ca(OH)}_2\) dose: \( 1.14 \, \text{mmol/L} \)
- Molar mass of \(\text{Ca(OH)}_2\): \( 74 \, \text{g/mol} \)

### Step 1: Convert volume of water to liters
Since 1 cubic meter (m\(^3\)) = 1000 liters (L), we have:

\[
21,000,000 \, \text{m}^3 \times 1000 = 21,000,000,000 \, \text{L}
\]

### Step 2: Convert concentration to moles of \(\text{Ca(OH)}_2\)
Given the concentration of \(\text{Ca(OH)}_2\) is \(1.14 \, \text{mmol/L}\), we first convert this to mol/L:

\[
1.14 \, \text{mmol/L} = 1.14 \times 10^{-3} \, \text{mol/L}
\]

Now, multiply this concentration by the total volume of water in liters to find the total moles of \(\text{Ca(OH)}_2\):

\[
1.14 \times 10^{-3} \, \text{mol/L} \times 21,000,000,000 \, \text{L} = 23,940,000 \, \text{mol}
\]

### Step 3: Convert moles to mass
Now, using the molar mass of \(\text{Ca(OH)}_2\), which is \(74 \, \text{g/mol}\), we can convert moles to grams:

\[
23,940,000 \, \text{mol} \times 74 \, \text{g/mol} = 1,770,360,000 \, \text{g}
\]

Convert grams to kilograms (since 1 kg = 1000 g):

\[
1,770,360,000 \, \text{g} = 1,770,360 \, \text{kg}
\]

### Step 4: Convert kilograms to kiloton
Since 1 kiloton (kton) = 1,000,000 kg, we convert:

\[
1,770,360 \, \text{kg} = 1.77 \, \text{kton}
\]

### Final Answer:
The amount of \(\text{Ca(OH)}_2\) dosed per year is **2 kton** (rounded to 0 decimals).

Would you like further details or have any questions?

Here are 5 related questions:
1. What are other chemicals used in water treatment and their dosages?
2. How does calcium hydroxide soften water?
3. How do you calculate the molar mass of a compound?
4. What is the significance of millimolar (mmol/L) in chemical dosing?
5. How is the efficiency of water treatment plants measured?

**Tip:** Always double-check unit conversions when working with large volumes and dosages.

A drinking water treatment plant softens 21000000 m³ per year by dosing 1.14 mmol/L Ca(OH)₂. Molar mass of Ca(OH)₂ is 74 g/mol. Calculate the amount of Ca(OH)₂ dosed per year in kton, with 0 decimals.

Discover how to calculate the amount of calcium hydroxide (Ca(OH)₂) dosed in a water treatment plant processing 21 million m³ per year with a concentration of 1.14 mmol/L. This problem involves unit conversions, molar mass, and dosage calculations, ideal for advanced high school or undergraduate chemistry students.

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