Math Problem Statement

Two years ago, you invested $3,150. Today, it is worth $3,900. What rate of interest did you earn?

Multiple Choice

11.27%

5.20%

.94%

5.64%

4.20%

Solution

To find the rate of interest earned, we can use the formula for compound interest, assuming the investment was compounded annually:

A=P(1+r)tA = P(1 + r)^t

Where:

  • AA is the final amount ($3,900),
  • PP is the initial principal ($3,150),
  • rr is the annual interest rate (expressed as a decimal),
  • tt is the time in years (2 years).

We need to solve for rr. First, rearrange the formula to isolate rr:

AP=(1+r)t\frac{A}{P} = (1 + r)^t

3,9003,150=(1+r)2\frac{3,900}{3,150} = (1 + r)^2

1.2381=(1+r)21.2381 = (1 + r)^2

Now, take the square root of both sides:

1.2381=1+r\sqrt{1.2381} = 1 + r

1.1127=1+r1.1127 = 1 + r

Now, subtract 1 from both sides:

r=0.1127r = 0.1127

Convert rr to a percentage:

r=11.27%r = 11.27\%

Thus, the interest rate is 11.27%.

Would you like further details or have any questions?


Here are 5 related questions:

  1. How would the formula change for monthly compounding?
  2. How would the interest rate change if the investment period was longer?
  3. What is the formula for continuously compounded interest?
  4. How does compound interest differ from simple interest?
  5. Can interest rates vary within a fixed investment period?

Tip: Always ensure the time period tt aligns with how the interest is compounded (annually, monthly, etc.).

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Math Problem Analysis

Mathematical Concepts

Compound Interest
Algebra

Formulas

A = P(1 + r)^t
r = (A/P)^(1/t) - 1

Theorems

Compound Interest Formula

Suitable Grade Level

Grades 9-12